[proto] Proto Transform Questions

2011-01-15 Thread Nate Knight
y handling them all). Also, as written the transform doesn't recurse properly, and I'm having some trouble seeing how to correct this. As I'm really just trying to get my mind around how proto works, any comments would be appreciated. Thanks Nate Knight test2.c

Re: [proto] Proto Transform Questions

2011-01-15 Thread Nate Knight
On Jan 14, 2011, at 12:29 PM, Nate Knight wrote: > I've pasted some code below where I am trying to transform expressions of the > form > > (a op b op c)[i] > > to > > (a[i] op b[i] op c[i]) > > I managed to get this to work for the simple case > >

Re: [proto] Proto Transform Questions

2011-01-18 Thread Nate Knight
Eric Niebler writes: > > This is a fun little problem. The answer is very simple, but requires > some knowledge of proto's pass_through transform, possessed by > proto::nary_expr (and friends): > Eric, Thanks for the pointers. I had tried this with nary_expr, but had some trouble distributin

[proto] pod_generator Question

2011-02-11 Thread Nate Knight
I see in the Proto documentation a trick for getting the Proto operator overloads found by ADL using something like template struct my_complex { BOOST_PROTO_EXTENDS( typename proto::terminal >::type , my_complex , proto::default_domain ) }; The proto::pod_generator cl

Re: [proto] pod_generator Question

2011-02-12 Thread Nate Knight
> On 2/12/2011 7:17 AM, Nate Knight wrote: >> I see in the Proto documentation a trick for getting the Proto operator >> overloads found by ADL using something like >> >> template >> struct my_complex >> { >>BOOST_PROTO_EXTENDS( >>ty

Re: [proto] pod_generator Question

2011-02-13 Thread Nate Knight
> The second argument to BOOST_PROTO_DEFINE_OPERATORS is a domain. When > defining a domain you (usually) specify a generator with an expression > wrapper. What are you using for a domain, and how do you define it? > > When I want an end-user-friendly terminal type, I derive it from the > express

Re: [proto] proto performance

2011-02-24 Thread Nate Knight
On Feb 20, 2011, at 4:43 AM, Joel Falcou wrote: > On 20/02/11 12:41, Eric Niebler wrote: >> On 2/20/2011 6:40 PM, Joel Falcou wrote: >>> On 20/02/11 12:31, Karsten Ahnert wrote: It is amazing that the proto expression is faster then the naive one. The compiler must really love the way p

Re: [proto] proto performance

2011-02-24 Thread Nate Knight
Not sure what happened to those tables. I'll try again. MacBook Pro, 10.6.6, Core 2 Duo ProtoContextProtoTransform ProtoLambda Loop GCC 4.2.1 (Apple) : 5.3565438 5.3721942 126.38458 1.3657978 GCC 4.4.5 : 1.8878364 1.8845548

[proto] Nested Transforms

2011-02-25 Thread Nate Knight
I'm trying to understand why the two commented out lines fail to compile. It seems to me that ideally they would compile, but I may be missing some constraint that makes these lines incorrect. In the first case, it seems like the return type of the default subscript evaluator is being compu

Re: [proto] Nested Transforms

2011-02-28 Thread Nate Knight
On Feb 26, 2011, at 4:55 AM, Eric Niebler wrote: > On 2/26/2011 8:18 AM, Nate Knight wrote: >> >> int main() >> { >>la::state_type x = {1.0,2.0}; >>la::state_type const& xc = x; >> >>// this compiles >>la::EvalOpt()( lit

Re: [proto] vector of proto expressions

2011-03-18 Thread Nate Knight
> > In pseudo code it should look like this: > > Expressions< N > expressions; > construct( expressions );// or something similar > do_step( epxressions , x ); // my method How about something like? ~ #include using namespace boost::proto; template void my_met

Re: [proto] vector of proto expressions

2011-03-18 Thread Nate Knight
On Mar 18, 2011, at 9:17 AM, Karsten Ahnert wrote: > Hmm, this might work. It is similar to > > my_method( fusion::make_vector( i+i , i*i*i , i*i ) , x ); > > But the expression might become really large, say 100 elements. A > separation between construction and usage would be nicer. How about