Thanks much.
Regards
Saptarshi

On Sat, Dec 12, 2009 at 4:40 PM, Kenton Varda <ken...@google.com> wrote:
> Actually, this is a better link:
> http://code.google.com/apis/protocolbuffers/docs/reference/cpp/google.protobuf.common.html#SetLogHandler.details
> For some reason the auto-generated documentation is failing to hyperlink to
> the definition of LogHandler, but it is shown among the typedefs at the top
> of that page:
> typedef void LogHandler(LogLevel level, const char *filename, int line,
> const string &message)
> On Sat, Dec 12, 2009 at 1:36 PM, Kenton Varda <ken...@google.com> wrote:
>>
>> All messages are written to stderr (not stdout), which is usually reserved
>> for human-readable error messages.  However, you can redirect the messages
>> using google::protobuf::SetLogHandler() as documented here:
>>
>> http://code.google.com/apis/protocolbuffers/docs/reference/cpp/google.protobuf.common.html#SetLogHandler
>>
>> On Sat, Dec 12, 2009 at 10:50 AM, Saptarshi Guha
>> <saptarshi.g...@gmail.com> wrote:
>>>
>>> Hello,
>>> I am using Protocol Buffers to serialize some data.
>>> To begin with I do realize that I shouldn't be using PB for
>>> serializing very large messages, but given that I am, I have to deal
>>> with these messages.
>>>
>>> E.g I have a message of 381MB, so naturally I get this error when
>>> parsing:
>>>
>>> libprotobuf ERROR google/protobuf/io/coded_stream.cc:196] A protocol
>>> message was rejected because it was too big (more than 67108864
>>> bytes).  To increase the limit (or to disable these warnings), see
>>> CodedInputStream::SetTotalBytesLimit() in
>>> google/protobuf/io/coded_stream.h.
>>>
>>>
>>> I viewed the header file and see what I have to do next. I'll fix my
>>> code soon, till then:
>>>
>>> My program redirects standard error(and output) and re-encodes
>>> functions that write to these streams. However writing to s.out and
>>> s.err are through special functions. PB, does not use my functions.
>>> Other libraries (and I only use PB) writing to s.err and s.out can
>>> adversely affect my program.
>>>
>>> Q. Is there a flag I can set to not display the warning? i.e silently
>>> fail? I'm not using CodedInputstream, instead I use ParseFromArray (i
>>> have read in the bytes with m own functions)
>>>
>>> Regards
>>> Saptarshi
>>>
>>> --
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>>
>
>

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