You probably shouldn't rely on this. Some of the serialization methods will
guarantee this, some won't. What you can do is call ByteSize() yourself,
and then use SerializeWithCachedSizes(), which requires that ByteSize() was
already called and won't call it again. You'll have to do a small
Kenton Varda, el 19 de septiembre a las 16:12 me escribiste:
You probably shouldn't rely on this. Some of the serialization methods will
guarantee this, some won't. What you can do is call ByteSize() yourself,
and then use SerializeWithCachedSizes(), which requires that ByteSize() was
