reply to self: I guess you copy the item from the end of the list into the space formerly occupied by the item you want to delete, then call RemoveLast()...
On Sep 16, 4:27 pm, [EMAIL PROTECTED] wrote: > OK, rephrase that question. Say you have a releated field containing > 10 items. You wish to delete the 2nd item so that the list contains 9 > items and foo_size() returns 9. Is that possible? > > I can't see an erase() function in mutable_foo(), and I can't see > anything in RepeatedField that decrements current_size_ other than > RemoveLast() which presumably will only remove the _last_ item? > > Currently the only way to remove elements from a list seems to be > awful hacks like a.parse(a.serialise()) after clearing the items you > want to delete > > On Aug 12, 9:05 pm, "Kenton Varda" <[EMAIL PROTECTED]> wrote: > > > For C++, use the RepeatedField > > interfaces:http://code.google.com/apis/protocolbuffers/docs/reference/cpp/google... > > > You can get a mutable pointer to a RepeatedField or RepeatedPtrField that > > represents a field named "foo" by calling the message's "mutable_foo()" > > accessor. > > > For Python, I think you currently have to clear the field and repopulate it. > > > On Tue, Aug 12, 2008 at 12:22 PM, <[EMAIL PROTECTED]> wrote: > > > > Python or C++ > > > > On Aug 12, 8:12 pm, "Kenton Varda" <[EMAIL PROTECTED]> wrote: > > > > In what language? > > > > > On Tue, Aug 12, 2008 at 12:11 PM, <[EMAIL PROTECTED]> wrote: > > > > > > Given an object containing a repeated field, is it possible to remove > > > > > some arbitrary element from that list? --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Protocol Buffers" group. To post to this group, send email to protobuf@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/protobuf?hl=en -~----------~----~----~----~------~----~------~--~---
