Yes. It will replace the value with the same key.
On Sat, Jun 24, 2017 at 11:08 AM Marc Gravell
wrote:
> Basically, if I have
>
> message Foo {
> int32 x = 1;
> int32 y = 2;
> }
> message Bar {
> map items = 1;
> }
>
> And I serialize 2 fragments
Basically, if I have
message Foo {
int32 x = 1;
int32 y = 2;
}
message Bar {
map items = 1;
}
And I serialize 2 fragments appended:
items = { 1: { x: 123 } }
and (as the second appended chunk)
items = { 1: { y: 456 } }
And now I deserialize the entire chunk; is the