[protobuf] Re: What is the default value for a message used as a field type within another message?
Thanks for the quick reply -- I noticed this in the documentation
after searching for default instance:
For embedded messages, the default value is always the default
instance or prototype of the message, which has none of its fields
set. So, does this mean that even the required fields will be set to
their default values in this prototype object? Or is there some other
algorithm for the values of the fields within the prototype/default
instance?
For broader context, I'm trying to figure out how to determine if an
optional field was actually set in the transmitted protocol buffer or
whether its default value was filled in automatically.
In reference to the example below, if the title field had been set to
Field of Dreams and then the user set it to an empty string , I
would want to actually update the value in my data store to be the
empty string. However, if the user didn't change the title field at
all, I will still see an empty string in the title field when I try
and get at the field through the accessor. I'm looking for a way to
setup my protocol buffer format so I can distinguish between those two
cases.
Thanks again.
On Jun 4, 9:45 am, Jason Hsueh jas...@google.com wrote:
No, protobuf accessors never return null. For message fields, you get the
default instance of the message type.
On Fri, Jun 4, 2010 at 9:32 AM, Jax jax...@gmail.com wrote:
This should be pretty straightforward, but I couldn't find it in any
of the documentation on default values.
A slight change from some example code in the google documentation:
message SearchResponse {
optional Result result = 1;
}
message Result {
required string url = 1;
optional string title = 2;
repeated string snippets = 3;
}
My question is, what is the default value for the Result in the above
code? Does it get set to null since (I presume) it will be compiled
into an object when the protocol buffer gets compiled into Java or C#?
Or do default values work differently for a nested message than for
base types?
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Re: [protobuf] Re: What is the default value for a message used as a field type within another message?
Use the has accessors to determine whether the field was explicitly set.
Java: message.hasFoo()
C++: message.has_foo()
Python: message.HasField(foo) # (I think; check docs)
On Fri, Jun 4, 2010 at 10:18 AM, Jax jax...@gmail.com wrote:
Thanks for the quick reply -- I noticed this in the documentation
after searching for default instance:
For embedded messages, the default value is always the default
instance or prototype of the message, which has none of its fields
set. So, does this mean that even the required fields will be set to
their default values in this prototype object? Or is there some other
algorithm for the values of the fields within the prototype/default
instance?
For broader context, I'm trying to figure out how to determine if an
optional field was actually set in the transmitted protocol buffer or
whether its default value was filled in automatically.
In reference to the example below, if the title field had been set to
Field of Dreams and then the user set it to an empty string , I
would want to actually update the value in my data store to be the
empty string. However, if the user didn't change the title field at
all, I will still see an empty string in the title field when I try
and get at the field through the accessor. I'm looking for a way to
setup my protocol buffer format so I can distinguish between those two
cases.
Thanks again.
On Jun 4, 9:45 am, Jason Hsueh jas...@google.com wrote:
No, protobuf accessors never return null. For message fields, you get the
default instance of the message type.
On Fri, Jun 4, 2010 at 9:32 AM, Jax jax...@gmail.com wrote:
This should be pretty straightforward, but I couldn't find it in any
of the documentation on default values.
A slight change from some example code in the google documentation:
message SearchResponse {
optional Result result = 1;
}
message Result {
required string url = 1;
optional string title = 2;
repeated string snippets = 3;
}
My question is, what is the default value for the Result in the above
code? Does it get set to null since (I presume) it will be compiled
into an object when the protocol buffer gets compiled into Java or C#?
Or do default values work differently for a nested message than for
base types?
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[protobuf] Re: What is the default value for a message used as a field type within another message?
Perfect, just what I was looking for. Thanks much.
On Jun 4, 10:27 am, Kenton Varda ken...@google.com wrote:
Use the has accessors to determine whether the field was explicitly set.
Java: message.hasFoo()
C++: message.has_foo()
Python: message.HasField(foo) # (I think; check docs)
On Fri, Jun 4, 2010 at 10:18 AM, Jax jax...@gmail.com wrote:
Thanks for the quick reply -- I noticed this in the documentation
after searching for default instance:
For embedded messages, the default value is always the default
instance or prototype of the message, which has none of its fields
set. So, does this mean that even the required fields will be set to
their default values in this prototype object? Or is there some other
algorithm for the values of the fields within the prototype/default
instance?
For broader context, I'm trying to figure out how to determine if an
optional field was actually set in the transmitted protocol buffer or
whether its default value was filled in automatically.
In reference to the example below, if the title field had been set to
Field of Dreams and then the user set it to an empty string , I
would want to actually update the value in my data store to be the
empty string. However, if the user didn't change the title field at
all, I will still see an empty string in the title field when I try
and get at the field through the accessor. I'm looking for a way to
setup my protocol buffer format so I can distinguish between those two
cases.
Thanks again.
On Jun 4, 9:45 am, Jason Hsueh jas...@google.com wrote:
No, protobuf accessors never return null. For message fields, you get the
default instance of the message type.
On Fri, Jun 4, 2010 at 9:32 AM, Jax jax...@gmail.com wrote:
This should be pretty straightforward, but I couldn't find it in any
of the documentation on default values.
A slight change from some example code in the google documentation:
message SearchResponse {
optional Result result = 1;
}
message Result {
required string url = 1;
optional string title = 2;
repeated string snippets = 3;
}
My question is, what is the default value for the Result in the above
code? Does it get set to null since (I presume) it will be compiled
into an object when the protocol buffer gets compiled into Java or C#?
Or do default values work differently for a nested message than for
base types?
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