On Fri, Sep 19, 2008 at 7:39 PM, Leandro Lucarella <[EMAIL PROTECTED]> wrote:
>
> Kenton Varda, el 19 de septiembre a las 16:12 me escribiste:
> > You probably shouldn't rely on this. Some of the serialization methods
> will
> > guarantee this, some won't. What you can do is call ByteSize() your
Kenton Varda, el 19 de septiembre a las 16:12 me escribiste:
> You probably shouldn't rely on this. Some of the serialization methods will
> guarantee this, some won't. What you can do is call ByteSize() yourself,
> and then use SerializeWithCachedSizes(), which requires that ByteSize() was
> al
You probably shouldn't rely on this. Some of the serialization methods will
guarantee this, some won't. What you can do is call ByteSize() yourself,
and then use SerializeWithCachedSizes(), which requires that ByteSize() was
already called and won't call it again. You'll have to do a small amoun
