Hi,
I assume you're not using the insertion option on your Ajax.Updater
calls[1]? If so, there's your answer. If not, can you put together a
small, self-contained example that demonstrates the prblem?
[1] http://www.prototypejs.org/api/ajax/updater
HTH,
--
T.J. Crowder
tj / crowder software
Hello,
whats this? I have an another problem... :-)
- Original Message -
From: Diodeus [EMAIL PROTECTED]
To: Prototype script.aculo.us prototype-scriptaculous@googlegroups.com
Sent: Friday, November 28, 2008 5:01 PM
Subject: [Proto-Scripty] Re: prototype weight
You can get a
Hello Tobie,
you meant, that i send my code to
you?
- Original Message -
From: Tobie Langel [EMAIL PROTECTED]
To: Prototype script.aculo.us prototype-scriptaculous@googlegroups.com
Sent: Friday, November 28, 2008 5:02 PM
Subject: [Proto-Scripty] Re: prototype weight
Well, best
Is it the answer for my problem?
- Original Message -
From: Jamie [EMAIL PROTECTED]
To: Prototype script.aculo.us prototype-scriptaculous@googlegroups.com
Sent: Saturday, November 29, 2008 2:54 PM
Subject: [Proto-Scripty] Re: Window Scrolling -- sortables.create() and
scroll:window arg
Hi,
Not immediately seeing a problem, can you create a complete page that
demonstrates what you're seeing?
--
T.J. Crowder
tj / crowder softare / com
On Nov 30, 8:07 pm, Stucture_Ulf [EMAIL PROTECTED]
wrote:
thanks for your answer. here is a short code snippet i'm using. i do
not want to
Hello all
I am having a little trouble with IE6 and this snippet of code:
document.observe('dom:loaded', function() {
$(
$$('.blockbody').invoke('hide'),
$$('.hint').invoke('hide'),
Hi Grant,
You only need $() to extend elements that have not already been
extended. $$() extends the elements it returns[1]. Also, the only
reason to call $() is if you're doing something with the return value,
which in the given code you're not.
[1] http://prototypejs.org/api/utility/dollar
Thanks TJ
An example of where I have it in use is:
http://www.sydneycommunitycollege.com.au/courses/sport/dance
And even after copy/paste of your code, I still get the error.
Thanks
Grant
On 01/12/2008, at 4:35 PM, T.J. Crowder wrote:
Hi Grant,
You only need $() to extend
