How to setup base class so that subclasses don't neet to call $super
in their initialize method (because they might skip this call or call
with wrong parameters) ?
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Have you ever considered not including the initialize method in the
subclass?
Perhaps your baseclass can check if there's a child 'constructor' present
and automatically call that:
var MySuper = Class.create({
initialize: function() {
// do stuff
if (this.childConstructor) {
Thanks, it's usefull !
On 3 янв, 16:34, Johan Arensman johanm...@gmail.com wrote:
Have you ever considered not including the initialize method in the
subclass?
Perhaps your baseclass can check if there's a child 'constructor' present
and automatically call that:
var MySuper =
