Hi, On Jan 15, 12:17 am, BeiMingyu <cwen1...@gmail.com> wrote: > I‘am reading the source code of Function#methodize() (version1.7). > But I can't quite understand it. > 1. How can a function apply to null? code: return > __method.apply(null, a);
If you pass `null` or `undefined` in as the `thisArg` argument of `call` or `apply`, the global object is used as `thisArg`. (The global object is `window` on browsers.) See http://es5.github.com/#x15.3.4.3 > 2. want does it mean "return this._methodized = function(){}"? Does > it mean"this._methodized = function(){}; return this._methodized?" Effectively, yes. The form "x = y" is called an assignment expression. Like most (all?) expressions, the expression has a value: The value being assigned. And so "w = x = y;" means "w = (x = y);" Note that it's the value, not the code, that gets reused. So in "x = y = foo();", the call to `foo` only happens once; the return value of `foo` is the value used in "x = y = <value>". See http://es5.github.com/#x11.13.1 HTH, -- T.J. Crowder Independent Software Engineer tj / crowder software / com www / crowder software / com -- You received this message because you are subscribed to the Google Groups "Prototype & script.aculo.us" group. To post to this group, send email to prototype-scriptaculous@googlegroups.com. To unsubscribe from this group, send email to prototype-scriptaculous+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/prototype-scriptaculous?hl=en.
