Hi,
You're looking for the onException callback[1]. If an exception
occurs during script evaluation (or for any other reason during the
processing of the request), onException is called. You might want to
check ou the Bulletproof Ajax Requests How To in the unofficial
wiki[2], although what's there so far is just a start.
[1] http://prototypejs.org/api/ajax/options
[2] http://proto-scripty.wikidot.com/prototype:how-to-bulletproof-ajax-requests
HTH,
--
T.J. Crowder
tj / crowder software / com
On Nov 7, 2:14 pm, jaap.taal [EMAIL PROTECTED] wrote:
That's not what I want.
I want to serve text/javascript but when I'm using a dynamically
generated script which contains syntax errors I'm not notified by
Prototype.
On Nov 6, 8:57 pm, Diodeus [EMAIL PROTECTED] wrote:
Serve it as text/html.
On Nov 6, 2:06 pm, jaap.taal [EMAIL PROTECTED] wrote:
I'm using Ajax.Request and receive a text/javascript content-type, but
sometimes I make a syntax error in my javascript. The error is now
silently ignored (at least that's what I think). Using firebug it
doesn't show in my console window.
new Ajax.Request('myscript.php', {
method:'get',
paramters: {...}
});
Response:
HTTP/1.1 200 OK
Date: Thu, 06 Nov 2008 18:56:06 GMT
Server: Apache/2.2.9 (Debian) PHP/5.2.6-5 with Suhosin-Patch
X-Powered-By: PHP/5.2.6-5
Set-Cookie: PHPSESSID=...; path=/
Content-Length: 195
Connection: close
Content-Type: text/javascript
alert('testing';
How can I trap this error when I'm using prototype??
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