[Proto-Scripty] Re: Prototype and forms
Thanks for the cleanup. I have made those changes. Feel free to post
others. The problem I have is that the form had two dynamic places:
div id=territories/div
and
div id=adjForm/div
There is an onChange that calls the javascript function getTerritories
() allows the
div id=territories/div to display which has a form element
called territory. At the end of the same function, it calls the other
javascript function getAdjForm(). getAdjForm() looks to see if the
form element territory exists. That's the problem, for some reason, it
cannot see it. What can I do to make it where it does not fail the if
statement in that function?
On Jun 16, 11:33 am, Rick Waldron waldron.r...@gmail.com wrote:
A few things...
var params = Form.serialize($('createAdjForm'));
You can clean this up as:
var params = $('createAdjForm').serialize();
There are other points that you could optimize, but thats not your
question...
And at whatever point you want adjForm to appear, you need to add:
$('adjForm').show()
Rick
On Mon, Jun 15, 2009 at 5:46 PM, anthony mrsmi...@gmail.com wrote:
I have a form that when a user selects something from a drop-down,
another element in the form appears. There is another piece of the
form, that is never showing up, I need to understand what I am doing
wrong and how to fix it:
script type=text/javascript language=JavaScript
function getAdjForm() {
var params = Form.serialize($('createAdjForm'));
alert($('territory').value);
if ($('adjType').value !== $('territory').value !== ){
new Ajax.Updater(
adjForm,
?= $this-url(array('controller'='index',
'action'='get-adj-
form'))?,
{method:'post',
parameters: params});
}
}
function getTerritories() {
var params = Form.serialize($('createAdjForm'));
new Ajax.Updater(
territories,
?= $this-url(array('controller'='index', 'action'='get-
territories'))?,
{method:'post',
parameters: params});
if ($('adjType').value !== ){
//alert('d');
getAdjForm();
}
}
function getCustomer() {
var params = Form.serialize($('createAdjForm'));
new Ajax.Updater(
customer,
?= $this-url(array('controller'='index', 'action'='get-
customer'))?,
{method:'post',
parameters: params});
}
/script
form method=POST id=createAdjForm action=
p
table border=0 CELLSPACING=10
tr
td
bSelect Adjustment Type/b
/td
td
?php echo $this-formSelect('adjType',
$this-adjType, array
(onChange=getAdjForm()), array(=Select an Adjustment Type) +
$this-adjTypes) ?
/td
/tr
tr
td
bSubmitting Territory/b
/td
td
?php echo $this-formSelect('shortTerritory',
$this-
shortTerritory, array(onChange=getTerritories()), array
(=Select a Territory) + $this-shortTerritories) ?
div id=territories/div
/td
/tr
tr
td valign=top
bJustification/b
/td
td
?php echo
$this-formTextarea('justification',$this-
justification,array(rows=5,cols=75)) ?
/td
/tr
/table
hr
div id=adjForm
/div
***
This issue is that the data that should be here:
div id=adjForm
/div
Is never showing. When getAdjForm(); is called from getTerritories(),
the $('territory').value !== seems to be the problem. Does the
browser not know that was an element because it just appeared?
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups
Prototype script.aculo.us group.
To post to this group, send email to prototype-scriptaculous@googlegroups.com
To unsubscribe from this group, send email to
prototype-scriptaculous+unsubscr...@googlegroups.com
For more options, visit this group at
http://groups.google.com/group/prototype-scriptaculous?hl=en
-~--~~~~--~~--~--~---
[Proto-Scripty] Re: Prototype and forms
Ok, I have found a better way to explain this.
var params = $('createAdjForm').serialize();
alert(params);
This does not show the form elements that were included via: div
id=territories/div
Why is that the case?
On Jun 17, 9:06 am, anthony mrsmi...@gmail.com wrote:
Thanks for the cleanup. I have made those changes. Feel free to post
others. The problem I have is that the form had two dynamic places:
div id=territories/div
and
div id=adjForm/div
There is an onChange that calls the javascript function getTerritories
() allows the
div id=territories/div to display which has a form element
called territory. At the end of the same function, it calls the other
javascript function getAdjForm(). getAdjForm() looks to see if the
form element territory exists. That's the problem, for some reason, it
cannot see it. What can I do to make it where it does not fail the if
statement in that function?
On Jun 16, 11:33 am, Rick Waldron waldron.r...@gmail.com wrote:
A few things...
var params = Form.serialize($('createAdjForm'));
You can clean this up as:
var params = $('createAdjForm').serialize();
There are other points that you could optimize, but thats not your
question...
And at whatever point you want adjForm to appear, you need to add:
$('adjForm').show()
Rick
On Mon, Jun 15, 2009 at 5:46 PM, anthony mrsmi...@gmail.com wrote:
I have a form that when a user selects something from a drop-down,
another element in the form appears. There is another piece of the
form, that is never showing up, I need to understand what I am doing
wrong and how to fix it:
script type=text/javascript language=JavaScript
function getAdjForm() {
var params = Form.serialize($('createAdjForm'));
alert($('territory').value);
if ($('adjType').value !== $('territory').value !== ){
new Ajax.Updater(
adjForm,
?= $this-url(array('controller'='index',
'action'='get-adj-
form'))?,
{method:'post',
parameters: params});
}
}
function getTerritories() {
var params = Form.serialize($('createAdjForm'));
new Ajax.Updater(
territories,
?= $this-url(array('controller'='index', 'action'='get-
territories'))?,
{method:'post',
parameters: params});
if ($('adjType').value !== ){
//alert('d');
getAdjForm();
}
}
function getCustomer() {
var params = Form.serialize($('createAdjForm'));
new Ajax.Updater(
customer,
?= $this-url(array('controller'='index', 'action'='get-
customer'))?,
{method:'post',
parameters: params});
}
/script
form method=POST id=createAdjForm action=
p
table border=0 CELLSPACING=10
tr
td
bSelect Adjustment Type/b
/td
td
?php echo $this-formSelect('adjType',
$this-adjType, array
(onChange=getAdjForm()), array(=Select an Adjustment Type) +
$this-adjTypes) ?
/td
/tr
tr
td
bSubmitting Territory/b
/td
td
?php echo $this-formSelect('shortTerritory',
$this-
shortTerritory, array(onChange=getTerritories()), array
(=Select a Territory) + $this-shortTerritories) ?
div id=territories/div
/td
/tr
tr
td valign=top
bJustification/b
/td
td
?php echo
$this-formTextarea('justification',$this-
justification,array(rows=5,cols=75)) ?
/td
/tr
/table
hr
div id=adjForm
/div
***
This issue is that the data that should be here:
div id=adjForm
/div
Is never showing. When getAdjForm(); is called from getTerritories(),
the $('territory').value !== seems to be the problem. Does the
browser not know that was an element because it just appeared?
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups
Prototype script.aculo.us group.
To post to this group, send email to prototype-scriptaculous@googlegroups.com
To unsubscribe from this group, send email to
prototype-scriptaculous+unsubscr...@googlegroups.com
For more options, visit this group at
http://groups.google.com/group/prototype-scriptaculous?hl=en
-~--~~~~--~~--~--~---
[Proto-Scripty] Re: Prototype and forms
Because the contents are from an AJAX request and they dont exist in the
DOM probably .
OR..
They are outside the /form tag
Paste full code to a pastie and we can help
- Original Message -
From: anthony mrsmi...@gmail.com
To: Prototype script.aculo.us prototype-scriptaculous@googlegroups.com
Sent: Wednesday, June 17, 2009 4:52 PM
Subject: [Proto-Scripty] Re: Prototype and forms
Ok, I have found a better way to explain this.
var params = $('createAdjForm').serialize();
alert(params);
This does not show the form elements that were included via: div
id=territories/div
Why is that the case?
On Jun 17, 9:06 am, anthony mrsmi...@gmail.com wrote:
Thanks for the cleanup. I have made those changes. Feel free to post
others. The problem I have is that the form had two dynamic places:
div id=territories/div
and
div id=adjForm/div
There is an onChange that calls the javascript function getTerritories
() allows the
div id=territories/div to display which has a form element
called territory. At the end of the same function, it calls the other
javascript function getAdjForm(). getAdjForm() looks to see if the
form element territory exists. That's the problem, for some reason, it
cannot see it. What can I do to make it where it does not fail the if
statement in that function?
On Jun 16, 11:33 am, Rick Waldron waldron.r...@gmail.com wrote:
A few things...
var params = Form.serialize($('createAdjForm'));
You can clean this up as:
var params = $('createAdjForm').serialize();
There are other points that you could optimize, but thats not your
question...
And at whatever point you want adjForm to appear, you need to add:
$('adjForm').show()
Rick
On Mon, Jun 15, 2009 at 5:46 PM, anthony mrsmi...@gmail.com wrote:
I have a form that when a user selects something from a drop-down,
another element in the form appears. There is another piece of the
form, that is never showing up, I need to understand what I am doing
wrong and how to fix it:
script type=text/javascript language=JavaScript
function getAdjForm() {
var params = Form.serialize($('createAdjForm'));
alert($('territory').value);
if ($('adjType').value !== $('territory').value !== ){
new Ajax.Updater(
adjForm,
?= $this-url(array('controller'='index',
'action'='get-adj-
form'))?,
{method:'post',
parameters: params});
}
}
function getTerritories() {
var params = Form.serialize($('createAdjForm'));
new Ajax.Updater(
territories,
?= $this-url(array('controller'='index', 'action'='get-
territories'))?,
{method:'post',
parameters: params});
if ($('adjType').value !== ){
//alert('d');
getAdjForm();
}
}
function getCustomer() {
var params = Form.serialize($('createAdjForm'));
new Ajax.Updater(
customer,
?= $this-url(array('controller'='index', 'action'='get-
customer'))?,
{method:'post',
parameters: params});
}
/script
form method=POST id=createAdjForm action=
p
table border=0 CELLSPACING=10
tr
td
bSelect Adjustment Type/b
/td
td
?php echo $this-formSelect('adjType',
$this-adjType, array
(onChange=getAdjForm()), array(=Select an Adjustment Type) +
$this-adjTypes) ?
/td
/tr
tr
td
bSubmitting Territory/b
/td
td
?php echo $this-formSelect('shortTerritory',
$this-
shortTerritory, array(onChange=getTerritories()), array
(=Select a Territory) + $this-shortTerritories) ?
div id=territories/div
/td
/tr
tr
td valign=top
bJustification/b
/td
td
?php echo
$this-formTextarea('justification',$this-
justification,array(rows=5,cols=75)) ?
/td
/tr
/table
hr
div id=adjForm
/div
***
This issue is that the data that should be here:
div id=adjForm
/div
Is never showing. When getAdjForm(); is called from getTerritories(),
the $('territory').value !== seems to be the problem. Does the
browser not know that was an element because it just appeared?
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups
Prototype script.aculo.us group.
To post to this group, send email to prototype-scriptaculous@googlegroups.com
To unsubscribe from this group, send email to
prototype-scriptaculous+unsubscr...@googlegroups.com
For more options, visit this group at
http://groups.google.com/group/prototype-scriptaculous?hl=en
-~--~~~~--~~--~--~---
[Proto-Scripty] Re: Prototype and forms
Here was the problem.
I should have been calling the function (getAdjForm) using onComplete:
function getTerritories() {
var params = $('createAdjForm').serialize();
new Ajax.Updater(
territories,
?= $this-url(array('controller'='index', 'action'='get-
territories'))?,
{method:'post',
parameters: params,
onComplete: getAdjForm});
}
I have a lot to learn.
On Jun 17, 10:54 am, Alex McAuley webmas...@thecarmarketplace.com
wrote:
Because the contents are from an AJAX request and they dont exist in the
DOM probably .
OR..
They are outside the /form tag
Paste full code to a pastie and we can help
- Original Message -
From: anthony mrsmi...@gmail.com
To: Prototype script.aculo.us prototype-scriptaculous@googlegroups.com
Sent: Wednesday, June 17, 2009 4:52 PM
Subject: [Proto-Scripty] Re: Prototype and forms
Ok, I have found a better way to explain this.
var params = $('createAdjForm').serialize();
alert(params);
This does not show the form elements that were included via: div
id=territories/div
Why is that the case?
On Jun 17, 9:06 am, anthony mrsmi...@gmail.com wrote:
Thanks for the cleanup. I have made those changes. Feel free to post
others. The problem I have is that the form had two dynamic places:
div id=territories/div
and
div id=adjForm/div
There is an onChange that calls the javascript function getTerritories
() allows the
div id=territories/div to display which has a form element
called territory. At the end of the same function, it calls the other
javascript function getAdjForm(). getAdjForm() looks to see if the
form element territory exists. That's the problem, for some reason, it
cannot see it. What can I do to make it where it does not fail the if
statement in that function?
On Jun 16, 11:33 am, Rick Waldron waldron.r...@gmail.com wrote:
A few things...
var params = Form.serialize($('createAdjForm'));
You can clean this up as:
var params = $('createAdjForm').serialize();
There are other points that you could optimize, but thats not your
question...
And at whatever point you want adjForm to appear, you need to add:
$('adjForm').show()
Rick
On Mon, Jun 15, 2009 at 5:46 PM, anthony mrsmi...@gmail.com wrote:
I have a form that when a user selects something from a drop-down,
another element in the form appears. There is another piece of the
form, that is never showing up, I need to understand what I am doing
wrong and how to fix it:
script type=text/javascript language=JavaScript
function getAdjForm() {
var params = Form.serialize($('createAdjForm'));
alert($('territory').value);
if ($('adjType').value !== $('territory').value !== ){
new Ajax.Updater(
adjForm,
?= $this-url(array('controller'='index',
'action'='get-adj-
form'))?,
{method:'post',
parameters: params});
}
}
function getTerritories() {
var params = Form.serialize($('createAdjForm'));
new Ajax.Updater(
territories,
?= $this-url(array('controller'='index', 'action'='get-
territories'))?,
{method:'post',
parameters: params});
if ($('adjType').value !== ){
//alert('d');
getAdjForm();
}
}
function getCustomer() {
var params = Form.serialize($('createAdjForm'));
new Ajax.Updater(
customer,
?= $this-url(array('controller'='index', 'action'='get-
customer'))?,
{method:'post',
parameters: params});
}
/script
form method=POST id=createAdjForm action=
p
table border=0 CELLSPACING=10
tr
td
bSelect Adjustment Type/b
/td
td
?php echo $this-formSelect('adjType',
$this-adjType, array
(onChange=getAdjForm()), array(=Select an Adjustment Type) +
$this-adjTypes) ?
/td
/tr
tr
td
bSubmitting Territory/b
/td
td
?php echo $this-formSelect('shortTerritory',
$this-
shortTerritory, array(onChange=getTerritories()), array
(=Select a Territory) + $this-shortTerritories) ?
div id=territories/div
/td
/tr
tr
td valign=top
bJustification/b
/td
td
?php echo
$this-formTextarea('justification',$this-
justification,array(rows=5,cols=75)) ?
/td
/tr
/table
hr
div id=adjForm
/div
***
This issue is that the data that should be here:
div id=adjForm
/div
Is never showing. When getAdjForm(); is called from getTerritories(),
the $('territory').value !== seems to be the problem. Does the
browser not know that was an element because it just appeared?
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups
Prototype script.aculo.us group.
To post to this group, send email to prototype-scriptaculous@googlegroups.com
To unsubscribe from
[Proto-Scripty] Re: Prototype and forms
Always nice to find your own mistakes and learn from them - well done!
On Wed, Jun 17, 2009 at 12:30 PM, anthony mrsmi...@gmail.com wrote:
Here was the problem.
I should have been calling the function (getAdjForm) using onComplete:
function getTerritories() {
var params = $('createAdjForm').serialize();
new Ajax.Updater(
territories,
?= $this-url(array('controller'='index', 'action'='get-
territories'))?,
{method:'post',
parameters: params,
onComplete: getAdjForm});
}
I have a lot to learn.
On Jun 17, 10:54 am, Alex McAuley webmas...@thecarmarketplace.com
wrote:
Because the contents are from an AJAX request and they dont exist in the
DOM probably .
OR..
They are outside the /form tag
Paste full code to a pastie and we can help
- Original Message -
From: anthony mrsmi...@gmail.com
To: Prototype script.aculo.us
prototype-scriptaculous@googlegroups.com
Sent: Wednesday, June 17, 2009 4:52 PM
Subject: [Proto-Scripty] Re: Prototype and forms
Ok, I have found a better way to explain this.
var params = $('createAdjForm').serialize();
alert(params);
This does not show the form elements that were included via: div
id=territories/div
Why is that the case?
On Jun 17, 9:06 am, anthony mrsmi...@gmail.com wrote:
Thanks for the cleanup. I have made those changes. Feel free to post
others. The problem I have is that the form had two dynamic places:
div id=territories/div
and
div id=adjForm/div
There is an onChange that calls the javascript function getTerritories
() allows the
div id=territories/div to display which has a form element
called territory. At the end of the same function, it calls the other
javascript function getAdjForm(). getAdjForm() looks to see if the
form element territory exists. That's the problem, for some reason, it
cannot see it. What can I do to make it where it does not fail the if
statement in that function?
On Jun 16, 11:33 am, Rick Waldron waldron.r...@gmail.com wrote:
A few things...
var params = Form.serialize($('createAdjForm'));
You can clean this up as:
var params = $('createAdjForm').serialize();
There are other points that you could optimize, but thats not your
question...
And at whatever point you want adjForm to appear, you need to add:
$('adjForm').show()
Rick
On Mon, Jun 15, 2009 at 5:46 PM, anthony mrsmi...@gmail.com wrote:
I have a form that when a user selects something from a drop-down,
another element in the form appears. There is another piece of the
form, that is never showing up, I need to understand what I am
doing
wrong and how to fix it:
script type=text/javascript language=JavaScript
function getAdjForm() {
var params = Form.serialize($('createAdjForm'));
alert($('territory').value);
if ($('adjType').value !== $('territory').value !== ){
new Ajax.Updater(
adjForm,
?= $this-url(array('controller'='index',
'action'='get-adj-
form'))?,
{method:'post',
parameters: params});
}
}
function getTerritories() {
var params = Form.serialize($('createAdjForm'));
new Ajax.Updater(
territories,
?= $this-url(array('controller'='index', 'action'='get-
territories'))?,
{method:'post',
parameters: params});
if ($('adjType').value !== ){
//alert('d');
getAdjForm();
}
}
function getCustomer() {
var params = Form.serialize($('createAdjForm'));
new Ajax.Updater(
customer,
?= $this-url(array('controller'='index', 'action'='get-
customer'))?,
{method:'post',
parameters: params});
}
/script
form method=POST id=createAdjForm action=
p
table border=0 CELLSPACING=10
tr
td
bSelect Adjustment Type/b
/td
td
?php echo $this-formSelect('adjType',
$this-adjType, array
(onChange=getAdjForm()), array(=Select an Adjustment
Type) +
$this-adjTypes) ?
/td
/tr
tr
td
bSubmitting Territory/b
/td
td
?php echo $this-formSelect('shortTerritory',
$this-
shortTerritory, array(onChange=getTerritories()), array
(=Select a Territory) + $this-shortTerritories) ?
div id=territories/div
/td
/tr
tr
td valign=top
bJustification/b
/td
td
?php echo
$this-formTextarea('justification',$this-
justification,array(rows=5,cols=75)) ?
/td
/tr
/table
hr
div id=adjForm
/div
***
This issue is that the data that should be here:
div id=adjForm
/div
Is never showing. When getAdjForm(); is called from
getTerritories(),
the $('territory').value !== seems to be the problem. Does the
browser
[Proto-Scripty] Re: Prototype and forms
Maybe add it on onSuccess too ! just to be safe!
- Original Message -
From: anthony mrsmi...@gmail.com
To: Prototype script.aculo.us prototype-scriptaculous@googlegroups.com
Sent: Wednesday, June 17, 2009 5:30 PM
Subject: [Proto-Scripty] Re: Prototype and forms
Here was the problem.
I should have been calling the function (getAdjForm) using onComplete:
function getTerritories() {
var params = $('createAdjForm').serialize();
new Ajax.Updater(
territories,
?= $this-url(array('controller'='index', 'action'='get-
territories'))?,
{method:'post',
parameters: params,
onComplete: getAdjForm});
}
I have a lot to learn.
On Jun 17, 10:54 am, Alex McAuley webmas...@thecarmarketplace.com
wrote:
Because the contents are from an AJAX request and they dont exist in the
DOM probably .
OR..
They are outside the /form tag
Paste full code to a pastie and we can help
- Original Message -
From: anthony mrsmi...@gmail.com
To: Prototype script.aculo.us
prototype-scriptaculous@googlegroups.com
Sent: Wednesday, June 17, 2009 4:52 PM
Subject: [Proto-Scripty] Re: Prototype and forms
Ok, I have found a better way to explain this.
var params = $('createAdjForm').serialize();
alert(params);
This does not show the form elements that were included via: div
id=territories/div
Why is that the case?
On Jun 17, 9:06 am, anthony mrsmi...@gmail.com wrote:
Thanks for the cleanup. I have made those changes. Feel free to post
others. The problem I have is that the form had two dynamic places:
div id=territories/div
and
div id=adjForm/div
There is an onChange that calls the javascript function getTerritories
() allows the
div id=territories/div to display which has a form element
called territory. At the end of the same function, it calls the other
javascript function getAdjForm(). getAdjForm() looks to see if the
form element territory exists. That's the problem, for some reason, it
cannot see it. What can I do to make it where it does not fail the if
statement in that function?
On Jun 16, 11:33 am, Rick Waldron waldron.r...@gmail.com wrote:
A few things...
var params = Form.serialize($('createAdjForm'));
You can clean this up as:
var params = $('createAdjForm').serialize();
There are other points that you could optimize, but thats not your
question...
And at whatever point you want adjForm to appear, you need to add:
$('adjForm').show()
Rick
On Mon, Jun 15, 2009 at 5:46 PM, anthony mrsmi...@gmail.com wrote:
I have a form that when a user selects something from a drop-down,
another element in the form appears. There is another piece of the
form, that is never showing up, I need to understand what I am doing
wrong and how to fix it:
script type=text/javascript language=JavaScript
function getAdjForm() {
var params = Form.serialize($('createAdjForm'));
alert($('territory').value);
if ($('adjType').value !== $('territory').value !== ){
new Ajax.Updater(
adjForm,
?= $this-url(array('controller'='index',
'action'='get-adj-
form'))?,
{method:'post',
parameters: params});
}
}
function getTerritories() {
var params = Form.serialize($('createAdjForm'));
new Ajax.Updater(
territories,
?= $this-url(array('controller'='index', 'action'='get-
territories'))?,
{method:'post',
parameters: params});
if ($('adjType').value !== ){
//alert('d');
getAdjForm();
}
}
function getCustomer() {
var params = Form.serialize($('createAdjForm'));
new Ajax.Updater(
customer,
?= $this-url(array('controller'='index', 'action'='get-
customer'))?,
{method:'post',
parameters: params});
}
/script
form method=POST id=createAdjForm action=
p
table border=0 CELLSPACING=10
tr
td
bSelect Adjustment Type/b
/td
td
?php echo $this-formSelect('adjType',
$this-adjType, array
(onChange=getAdjForm()), array(=Select an Adjustment Type)
+
$this-adjTypes) ?
/td
/tr
tr
td
bSubmitting Territory/b
/td
td
?php echo $this-formSelect('shortTerritory',
$this-
shortTerritory, array(onChange=getTerritories()), array
(=Select a Territory) + $this-shortTerritories) ?
div id=territories/div
/td
/tr
tr
td valign=top
bJustification/b
/td
td
?php echo
$this-formTextarea('justification',$this-
justification,array(rows=5,cols=75)) ?
/td
/tr
/table
hr
div id=adjForm
/div
***
This issue is that the data that should be here:
div id=adjForm
/div
Is never showing. When getAdjForm(); is called from
getTerritories(),
the $('territory').value !== seems to be the problem. Does the
browser not know that was an element because it just appeared
[Proto-Scripty] Re: Prototype and forms
A few things...
var params = Form.serialize($('createAdjForm'));
You can clean this up as:
var params = $('createAdjForm').serialize();
There are other points that you could optimize, but thats not your
question...
And at whatever point you want adjForm to appear, you need to add:
$('adjForm').show()
Rick
On Mon, Jun 15, 2009 at 5:46 PM, anthony mrsmi...@gmail.com wrote:
I have a form that when a user selects something from a drop-down,
another element in the form appears. There is another piece of the
form, that is never showing up, I need to understand what I am doing
wrong and how to fix it:
script type=text/javascript language=JavaScript
function getAdjForm() {
var params = Form.serialize($('createAdjForm'));
alert($('territory').value);
if ($('adjType').value !== $('territory').value !== ){
new Ajax.Updater(
adjForm,
?= $this-url(array('controller'='index',
'action'='get-adj-
form'))?,
{method:'post',
parameters: params});
}
}
function getTerritories() {
var params = Form.serialize($('createAdjForm'));
new Ajax.Updater(
territories,
?= $this-url(array('controller'='index', 'action'='get-
territories'))?,
{method:'post',
parameters: params});
if ($('adjType').value !== ){
//alert('d');
getAdjForm();
}
}
function getCustomer() {
var params = Form.serialize($('createAdjForm'));
new Ajax.Updater(
customer,
?= $this-url(array('controller'='index', 'action'='get-
customer'))?,
{method:'post',
parameters: params});
}
/script
form method=POST id=createAdjForm action=
p
table border=0 CELLSPACING=10
tr
td
bSelect Adjustment Type/b
/td
td
?php echo $this-formSelect('adjType',
$this-adjType, array
(onChange=getAdjForm()), array(=Select an Adjustment Type) +
$this-adjTypes) ?
/td
/tr
tr
td
bSubmitting Territory/b
/td
td
?php echo $this-formSelect('shortTerritory',
$this-
shortTerritory, array(onChange=getTerritories()), array
(=Select a Territory) + $this-shortTerritories) ?
div id=territories/div
/td
/tr
tr
td valign=top
bJustification/b
/td
td
?php echo
$this-formTextarea('justification',$this-
justification,array(rows=5,cols=75)) ?
/td
/tr
/table
hr
div id=adjForm
/div
***
This issue is that the data that should be here:
div id=adjForm
/div
Is never showing. When getAdjForm(); is called from getTerritories(),
the $('territory').value !== seems to be the problem. Does the
browser not know that was an element because it just appeared?
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups
Prototype script.aculo.us group.
To post to this group, send email to prototype-scriptaculous@googlegroups.com
To unsubscribe from this group, send email to
prototype-scriptaculous+unsubscr...@googlegroups.com
For more options, visit this group at
http://groups.google.com/group/prototype-scriptaculous?hl=en
-~--~~~~--~~--~--~---
