Hi TJ,
Thank you for your response.
I will try your chained loop mechanism.
Greetinx,
Zjoske.
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Hi,
By default, Ajax.Request is *asynchronous*, so that code won't wait
for one to complete before it kicks off the next, so you'll end up
with multiple outstanding calls to the server. If you have more than
two outstanding calls, the odds are very high that the browser,
server, or both will que
