I knew it .. I knew if I asked(publicly) I would figure it out ....
****************
if($('subsidiary')==undefined)
{
var subsidiary = new Element('input',
{ 'type': 'text','value': 'test','name': 'test', 'id':
'subsidiary'} );
$('form_job_some_id').insert(subsidiary);
alert($F('subsidiary_".$data[orderid][$a]."')+'testafa');
}
***************
There is probably a better way to do that .. if you happen to know .. please
share.
Jimmy
On Tue, Mar 17, 2009 at 1:42 PM, Jimmy Brake <isu...@gmail.com> wrote:
> Hi,
>
> I am trying to add a hidden form element.
>
> if($('subsidiary')==undefined)
> {
> var subsidiary = new Element('subsidiary',
> { 'type': 'hidden','value': 'test','name': 'test'} );
>
> alert(\$F('subsidiary')+'testafa');
> }
>
> When I run that code .. I get 'element is null' in firebug.
>
> I have dug and dug on google .. (my assumption is that this must have been
> written about many times but I have not had any luck finding a working
> example).
>
> Any ideas?
>
> Thanks!
>
> Jimmy
>
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