RE: [Proto-Scripty] Variables in $$() ?????
You're passing a string constant to $$
input[type=radio][name='type'][value=selectThis])
'selectThis' will not be evaluated, as you seem to be expecting. Have a
loook at Tenplate to do what you want:
http://www.prototypejs.org/api/template
--
Jonathan Rosenberg
Founder Executive Director
Tabby's Place
http://www.tabbysplace.org http://www.tabbysplace.org/
-Original Message-
From: prototype-scriptaculous@googlegroups.com
[mailto:prototype-scriptacul...@googlegroups.com] On Behalf Of Phil Petree
Sent: Saturday, September 25, 2010 7:46 AM
To: prototype-scriptaculous@googlegroups.com
Subject: [Proto-Scripty] Variables in $$() ?
I've hit this in two seperate places and not exactly sure why...
(I think its the 18 hour days, 7 days a week... g)
If value is hard set with '3' the following works:
$$(input[type=radio][name='type'][value='3'])[0].writeAttribute(checked,
checked);
However, if we use a variable (selectThis) and assign it 3 it does not
work.
var selectThis;
selectThis = '3';
$$(input[type=radio][name='type'][value=selectThis])[0].writeAttribute(ch
ecked, checked);
Type casting doesn't work either:
var selectThis;
selectThis = String('3');
$$(input[type=radio][name='type'][value=selectThis])[0].writeAttribute(ch
ecked, checked);
I'm having the same problem here too (compare o.value== 'GA' and the select
gets set to GA):
selectThis = 'GA'
$$('select#ajstate option').each(function(o){
if(o.value==selectThis){o.selected = true;$break;}
});
What am I missing here?
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Re: [Proto-Scripty] Variables in $$() ?????
Jonathan,
Thanks for that but like most things in the prototype documentation, it
lacks the type of clarity that I can understand.
IOW, I can read the documentation, scratch my head and say huh? I leave that
documentation thinking this might be what I need but have no clue as to how
to implement that to solve my problem.
Which is exactly what happened here... OK, I need to use templates to
somehow sprintf the string constant into a direct value but huh?
On Sat, Sep 25, 2010 at 7:59 AM, Jonathan Rosenberg j...@tabbysplace.orgwrote:
You're passing a string constant to $$
input[type=radio][name='type'][value=selectThis])
'selectThis' will not be evaluated, as you seem to be expecting. Have a
loook at Tenplate to do what you want:
http://www.prototypejs.org/api/template
--
Jonathan Rosenberg
Founder Executive Director
Tabby's Place
http://www.tabbysplace.org
-Original Message-
*From:* prototype-scriptaculous@googlegroups.com [mailto:
prototype-scriptacul...@googlegroups.com] *On Behalf Of *Phil Petree
*Sent:* Saturday, September 25, 2010 7:46 AM
*To:* prototype-scriptaculous@googlegroups.com
*Subject:* [Proto-Scripty] Variables in $$() ?
I've hit this in two seperate places and not exactly sure why...
(I think its the 18 hour days, 7 days a week... g)
If value is hard set with '3' the following works:
$$(input[type=radio][name='type'][value='3'])[0].writeAttribute(checked,
checked);
However, if we use a variable (selectThis) and assign it 3 it does not
work.
var selectThis;
selectThis = '3';
$$(input[type=radio][name='type'][value=selectThis])[0].writeAttribute(checked,
checked);
Type casting doesn't work either:
var selectThis;
selectThis = String('3');
$$(input[type=radio][name='type'][value=selectThis])[0].writeAttribute(checked,
checked);
I'm having the same problem here too (compare o.value== 'GA' and the select
gets set to GA):
selectThis = 'GA'
$$('select#ajstate option').each(function(o){
if(o.value==selectThis){o.selected = true;$break;}
});
What am I missing here?
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Re: [Proto-Scripty] Variables in $$() ?????
OK, if I got this right and I don't think I do... because its selecting the
last state (WY) and not the state it should be selecting (FL)
var selectTemplate = new Template('o.value == #{matchString}');
selectThis = {matchString:
transport.responseXML.getElementsByTagName('state')[0].firstChild.nodeValue
};
$$('select#ajstate option').each(function(o){
if(selectTemplate.evaluate(selectThis)){o.selected = true;$break;}
});
The radio button seems to be working but I need to change the data to test
it:
var radioTemplate = new
Template('input[type=radio][name=#{selectID}][value=#{selectValue}]');
selectThis = {selectID: 'type', selectValue:
transport.responseXML.getElementsByTagName('type')[0].firstChild.nodeValue
};
$$(radioTemplate.evaluate(selectThis))[0].writeAttribute(checked,
checked);
On Sat, Sep 25, 2010 at 7:59 AM, Jonathan Rosenberg j...@tabbysplace.orgwrote:
You're passing a string constant to $$
input[type=radio][name='type'][value=selectThis])
'selectThis' will not be evaluated, as you seem to be expecting. Have a
loook at Tenplate to do what you want:
http://www.prototypejs.org/api/template
--
Jonathan Rosenberg
Founder Executive Director
Tabby's Place
http://www.tabbysplace.org
-Original Message-
*From:* prototype-scriptaculous@googlegroups.com [mailto:
prototype-scriptacul...@googlegroups.com] *On Behalf Of *Phil Petree
*Sent:* Saturday, September 25, 2010 7:46 AM
*To:* prototype-scriptaculous@googlegroups.com
*Subject:* [Proto-Scripty] Variables in $$() ?
I've hit this in two seperate places and not exactly sure why...
(I think its the 18 hour days, 7 days a week... g)
If value is hard set with '3' the following works:
$$(input[type=radio][name='type'][value='3'])[0].writeAttribute(checked,
checked);
However, if we use a variable (selectThis) and assign it 3 it does not
work.
var selectThis;
selectThis = '3';
$$(input[type=radio][name='type'][value=selectThis])[0].writeAttribute(checked,
checked);
Type casting doesn't work either:
var selectThis;
selectThis = String('3');
$$(input[type=radio][name='type'][value=selectThis])[0].writeAttribute(checked,
checked);
I'm having the same problem here too (compare o.value== 'GA' and the select
gets set to GA):
selectThis = 'GA'
$$('select#ajstate option').each(function(o){
if(o.value==selectThis){o.selected = true;$break;}
});
What am I missing here?
--
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Re: [Proto-Scripty] Variables in $$() ?????
David, although your suggestion doesn't throw any errors, it doesnt work
either... kinda wierd as I thought it would... and it would have been MUCH
simpler to implement too!
On Sat, Sep 25, 2010 at 8:57 AM, David Behler d.beh...@gmail.com wrote:
What about this:
$$(input[type=radio][name='type'][value=' + selectThis + '])
?
Am 25.09.2010 14:41, schrieb Phil Petree:
Jonathan,
Thanks for that but like most things in the prototype documentation, it
lacks the type of clarity that I can understand.
IOW, I can read the documentation, scratch my head and say huh? I leave
that documentation thinking this might be what I need but have no clue as
to how to implement that to solve my problem.
Which is exactly what happened here... OK, I need to use templates to
somehow sprintf the string constant into a direct value but huh?
On Sat, Sep 25, 2010 at 7:59 AM, Jonathan Rosenberg
j...@tabbysplace.orgwrote:
You're passing a string constant to $$
input[type=radio][name='type'][value=selectThis])
'selectThis' will not be evaluated, as you seem to be expecting. Have a
loook at Tenplate to do what you want:
http://www.prototypejs.org/api/template
--
Jonathan Rosenberg
Founder Executive Director
Tabby's Place
http://www.tabbysplace.org
-Original Message-
*From:* prototype-scriptaculous@googlegroups.com [mailto:
prototype-scriptacul...@googlegroups.com] *On Behalf Of *Phil Petree
*Sent:* Saturday, September 25, 2010 7:46 AM
*To:* prototype-scriptaculous@googlegroups.com
*Subject:* [Proto-Scripty] Variables in $$() ?
I've hit this in two seperate places and not exactly sure why...
(I think its the 18 hour days, 7 days a week... g)
If value is hard set with '3' the following works:
$$(input[type=radio][name='type'][value='3'])[0].writeAttribute(checked,
checked);
However, if we use a variable (selectThis) and assign it 3 it does not
work.
var selectThis;
selectThis = '3';
$$(input[type=radio][name='type'][value=selectThis])[0].writeAttribute(checked,
checked);
Type casting doesn't work either:
var selectThis;
selectThis = String('3');
$$(input[type=radio][name='type'][value=selectThis])[0].writeAttribute(checked,
checked);
I'm having the same problem here too (compare o.value== 'GA' and the
select gets set to GA):
selectThis = 'GA'
$$('select#ajstate option').each(function(o){
if(o.value==selectThis){o.selected = true;$break;}
});
What am I missing here?
--
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