[issue39013] SyntaxError: 'break' outside loop for legal Expression

2019-12-10 Thread Artem Tepanov
Artem Tepanov added the comment: Thx, after upgrade to: Python 3.8.1rc1 (tags/v3.8.1rc1:b00a2b5, Dec 10 2019, 01:13:53) [MSC v.1916 64 bit (AMD64)] on win32 All works fine, ...but Could you "pushing the person" which responsible for Web-Site please?, because I got Interp

[issue39013] SyntaxError: 'break' outside loop for legal Expression

2019-12-10 Thread Artem Tepanov
Artem Tepanov added the comment: Python 3.8.0 (tags/v3.8.0:fa919fd, Oct 14 2019, 19:37:50) [MSC v.1916 64 bit (AMD64)] on win32 Type "help", "copyright", "credits" or "license" for more information. >>> while False: ... if False: ...

[issue39013] SyntaxError: 'break' outside loop for legal Expression

2019-12-10 Thread Artem Tepanov
Artem Tepanov added the comment: Using cmd: C:\Users\ATepanov>python -V Python 3.8.0 C:\Users\ATepanov>python C:\Users\ATepanov\Desktop\Outside_The_Loop.py File "C:\Users\ATepanov\Desktop\Outside_The_Loop.py", line 3 break ^ SyntaxError: 'break' outside loop In Int

[issue39013] SyntaxError: 'break' outside loop for legal Expression

2019-12-10 Thread Artem Tepanov
New submission from Artem Tepanov : Why I can't execute this code: while False: if False: break print('WTF?') When I use repl.it or PyCharm on my work (Python 3.7) all works fine, yes I know this code looks silly, but it is a legal expression. About CPython Interpreter: C