New submission from Alexander Schier:
Return the total number of seconds contained in the duration. Equivalent to
(td.microseconds + (td.seconds + td.days * 24 * 3600) * 10**6) / 10**6
computed with true division enabled.
Should be
Return the total number of seconds contained in the
Tim Peters added the comment:
The docs look correct to me. For example,
from datetime import *
td = datetime.now() - datetime(1,1,1)
td
datetime.timedelta(735103, 61756, 484000)
td.total_seconds()
63512960956.484
^
What the
Alexander Schier added the comment:
Err, sorry my fault. Too late in the evening ;).
I saw the division by one million, but not the multiplation by one million
before. Additionally i was confused, because i expected that seconds are added
to each other in the parenthesis.
closing.
