[issue37494] Call asyncio Future in scope

Andrew Svetlov added the comment: It doesn't. Loop is executed by asyncio.run() (recommended) or low-level loop.run_until_complete() / loop.run_forever() calls. Please note, this tracker is for working on Python itself, not for teaching Python usage. Please use other resources like forums or

[issue37494] Call asyncio Future in scope

Fourcade added the comment: Here's the file with an example. The get_progress function always outputs 0. -- Added file: https://bugs.python.org/file48454/test_progress.py ___ Python tracker _

[issue37494] Call asyncio Future in scope

Fourcade added the comment: If I add a simple print inside long_task, the print is executed correctly. So it seems this code actually runs the loop. (I'm on python 3.6.8). -- ___ Python tracker __

[issue37494] Call asyncio Future in scope

Andrew Svetlov added the comment: Your code doesn't run the event loop, only creates it. What do you expect? -- ___ Python tracker ___

[issue37494] Call asyncio Future in scope

New submission from Fourcade : I'm trying to get the progession of my asyncIO Futures. For some reason, I can't get value updates inside any other scope. For example: ``` import concurrent.futures import time import asyncio import random def get_progress(futures): return sum([f.done() fo