[issue46228] argparse docs: default for prog= in ArgumentParser() should be basename of argv[0], not argv[0], to match behaviour

Change by paul j3 : -- nosy: +paul.j3 ___ Python tracker ___ ___ Python-bugs-list mailing list Unsubscribe:

[issue46228] argparse docs: default for prog= in ArgumentParser() should be basename of argv[0], not argv[0], to match behaviour

Raymond Hettinger added the comment: Thank you for the PR. -- nosy: +rhettinger resolution: -> fixed stage: patch review -> resolved status: open -> closed ___ Python tracker

[issue46228] argparse docs: default for prog= in ArgumentParser() should be basename of argv[0], not argv[0], to match behaviour

Change by miss-islington : -- keywords: +patch nosy: +miss-islington nosy_count: 2.0 -> 3.0 pull_requests: +28551 pull_request: https://github.com/python/cpython/pull/30339 ___ Python tracker

[issue46228] argparse docs: default for prog= in ArgumentParser() should be basename of argv[0], not argv[0], to match behaviour

Change by Éric Araujo : -- assignee: -> docs@python components: +Documentation nosy: +docs@python stage: -> patch review type: enhancement -> behavior versions: -Python 3.6, Python 3.7, Python 3.8 ___ Python tracker

[issue46228] argparse docs: default for prog= in ArgumentParser() should be basename of argv[0], not argv[0], to match behaviour

New submission from Jade Lovelace : Currently the documentation for argparse.ArgumentParser states that the default value of the prog[ram] argument is argv[0], however, this does not match the actual behaviour of the constructor. In reality, the constructor uses the basename of argv[0], as