Martin Panter added the comment:
IMO it might make sense in some cases to disallow subsequent reading from a
buffered socket reader (or probably any BufferedReader) that raises an
exception (not just a timeout). But the restriction seems unnecessary for
unbuffered raw readers, and it also
David Beazley added the comment:
This bug is still present in Python 3.5, but it occurs if you attempt to do a
readline() on a socket that's in non-blocking mode. In that case, you probably
DO want to retry at a later time (unlike the timeout case).
--
R. David Murray rdmur...@bitdance.com added the comment:
This patch has caused a non-trivial regression between 3.2 and 3.2.1. The
scenario in which I observed it is poplib. I create a POP3 connection with a
timeout. At one point in its processing, poplib is reading lines until it gets
a
Antoine Pitrou pit...@free.fr added the comment:
One could then continue processing, sending new transactions to the POP
server and getting responses.
That's optimistic. You don't know how much data has been lost in readline().
Sure, again your test server, it happens to work :) But again
R. David Murray rdmur...@bitdance.com added the comment:
I don't think it is optimistic. The poplib transaction pattern is: send a
command, get a response. If the response is not properly terminated, throw it
away. Send a new command, get a response. There's no ambiguity there. In
Changes by Florent Xicluna florent.xicl...@gmail.com:
--
nosy: +flox
___
Python tracker rep...@bugs.python.org
http://bugs.python.org/issue7322
___
___
Python-bugs-list
Gregory P. Smith g...@krypto.org added the comment:
If the server failed to close a transaction the protocol stream is over
unless you mime relying on hope and luck. Poplib has a nasty set of server
implementation bugs to work around here.
Readline as defined today no longer suits its needs but
R. David Murray rdmur...@bitdance.com added the comment:
Your suggestion sounds good to me.
I still think that it is a common failure mode in a client server transaction
for the server to fail to send a (complete) line that the client is expecting,
and vice versa, requiring a timeout, but not
Antoine Pitrou pit...@free.fr added the comment:
Committed in r88622 (3.3) and r88623 (3.2). The 2.7 implementation is too
different for the patch to apply, so if you want to fix it too, feel free to
upload a patch. Thank you!
--
resolution: - fixed
stage: patch review -
Antoine Pitrou pit...@free.fr added the comment:
Looks good and simple enough. I would probably shift the timeout test after the
closed test, but that's almost a detail.
--
___
Python tracker rep...@bugs.python.org
http://bugs.python.org/issue7322
David Beazley d...@dabeaz.com added the comment:
Just wanted to say that I agree it's nonsense to continue reading on a socket
that timed out (I'm not even sure what I might have been thinking when I first
submitted this bug other than just experimenting with edge cases of the socket
Ross Lagerwall rosslagerw...@gmail.com added the comment:
How about this?
Instead of just losing the data that's been read so far in readline(), this
patch adds the data as a new field to the exception that is thrown - this way
the semantics remain exactly the same but the data is not
David Beazley d...@dabeaz.com added the comment:
Have any other programming environments ever had a feature where a socket
timeout returns an exception containing partial data?I'm not aware of one
offhand and speaking as a systems programmer, something like this might be
somewhat
Antoine Pitrou pit...@free.fr added the comment:
This is an interesting approach. The problem is that AFAICT the issue is not
limited to readline. If you call e.g. read(1) and the socket times out
after having returned the first 5000 bytes, then those 5000 bytes might get
lost as well
Antoine Pitrou pit...@free.fr added the comment:
By the way, I recently fixed the makefile() documentation:
“The socket must be in blocking mode; it can have a timeout, but the file
object’s internal buffer may end up in a inconsistent state if a timeout
occurs.”
(in
Gregory P. Smith g...@krypto.org added the comment:
Generally there is no guarantee that a buffered object works properly when
the raw IO object raises some exception intermittently
I disagree. EINTR is a classic case of this and is something that buffering IO
layers deal with all the time.
Antoine Pitrou pit...@free.fr added the comment:
Generally there is no guarantee that a buffered object works
properly when the raw IO object raises some exception
intermittently
I disagree. EINTR is a classic case of this and is something that
buffering IO layers deal with all the time.
Ross Lagerwall rosslagerw...@gmail.com added the comment:
That complicates things quite a bit,
especially given that it has to be grafted on at least two layers of the
IO stack (the raw IO layer, and the buffered IO layer).
Also the TextIO layer I think.
That's my opinion too. So, instead,
Antoine Pitrou pit...@free.fr added the comment:
That's my opinion too. So, instead, of doing the above surgery inside
the IO stack, the SocketIO layer could detect the timeout and disallow
further access. What do you think?
So after a timeout occurs the file-object basically becomes
Ross Lagerwall rosslagerw...@gmail.com added the comment:
Attached patch disallows further reads after a timeout.
--
Added file: http://bugs.python.org/file20398/i7322.patch
___
Python tracker rep...@bugs.python.org
http://bugs.python.org/issue7322
Ross Lagerwall rosslagerw...@gmail.com added the comment:
Attached is a patch which fixes the issue.
Instead of allowing the readline method to lose data, it adds a check to
SocketIO.readinto() to ensure that the socket does not have a timeout and
throws an IOError if it does. Also does the
Changes by Ross Lagerwall rosslagerw...@gmail.com:
--
nosy: +loewis, pitrou
___
Python tracker rep...@bugs.python.org
http://bugs.python.org/issue7322
___
___
Antoine Pitrou pit...@free.fr added the comment:
While this patch looks conformant to the documentation, it is very likely to
break code in the wild. Even in the stdlib, there are uses of makefile() +
socket timeouts (e.g. in http.client and urllib). It would be better to find a
way to make
Ned Deily n...@acm.org added the comment:
I see Issue7995 also addresses the issue of accept sockets inheriting
nonblocking status and provides a suggested patch.
--
___
Python tracker rep...@bugs.python.org
http://bugs.python.org/issue7322
Roy Smith r...@panix.com added the comment:
I'm looking into this now. In the meantime, I've opened a marginally-related
bug, issue10473
--
nosy: +roysmith
___
Python tracker rep...@bugs.python.org
http://bugs.python.org/issue7322
Roy Smith r...@panix.com added the comment:
Ataching a test case which demonstrates the bug.
--
Added file: http://bugs.python.org/file19711/test-issue7322.py
___
Python tracker rep...@bugs.python.org
http://bugs.python.org/issue7322
Ned Deily n...@acm.org added the comment:
This would seem to be an invalid test case. It is specifically documented that
socket.makefile does not support this: The socket must be in blocking mode (it
can not have a timeout).
Roy Smith r...@panix.com added the comment:
This is kind of ugly. On the one hand, I'm all for adding a check in
makefile() to catch it being called on a non-blocking socket.
On the other hand, you are correct that a user could change the mode leter.
Even if we added checks for this in
Changes by Mark Lawrence breamore...@yahoo.co.uk:
--
stage: - needs patch
versions: +Python 2.7, Python 3.1, Python 3.2 -Python 2.6
___
Python tracker rep...@bugs.python.org
http://bugs.python.org/issue7322
___
New submission from David M. Beazley beaz...@users.sourceforge.net:
Consider a socket that has had a file-like wrapper placed around it
using makefile()
# s is a socket created previously
f = s.makefile()
Now, suppose that this socket has had a timeout placed on it.
s.settimeout(15)
If you
Changes by Gregory P. Smith g...@krypto.org:
--
assignee: - gregory.p.smith
nosy: +gregory.p.smith
priority: - normal
___
Python tracker rep...@bugs.python.org
http://bugs.python.org/issue7322
___
31 matches
Mail list logo