[issue13971] format() doesn't parse str.
New submission from umedoblock umedobl...@gmail.com:
format() mis understaning.
please pay attention to [0], [x].
d = {0: a, 0: A}
'd[0] = {0[0]}'.format(d)
'd[0] = a'
'd[0] = {0[0]}'.format(d)
Traceback (most recent call last):
File stdin, line 1, in module
KeyError: '0'
d2 = {x: 100}
'd2[x] = {0[x]}'.format(d2)
'd2[x] = 100'
--
components: Regular Expressions
messages: 152897
nosy: ezio.melotti, umedoblock
priority: normal
severity: normal
status: open
title: format() doesn't parse str.
type: behavior
versions: Python 3.2
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http://bugs.python.org/issue13971
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[issue13971] format() doesn't parse str.
Changes by Ezio Melotti ezio.melo...@gmail.com: -- nosy: +eric.smith ___ Python tracker rep...@bugs.python.org http://bugs.python.org/issue13971 ___ ___ Python-bugs-list mailing list Unsubscribe: http://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
[issue13971] format() doesn't parse str.
Eric V. Smith e...@trueblade.com added the comment: This is working as defined in PEP 3101: it calls PySequence_GetItem() or PyObject_GetItem() on the value inside the brackets. There is indeed no item in d that is the string 0 (including the quotes). -- assignee: - eric.smith resolution: - invalid stage: - committed/rejected status: open - closed ___ Python tracker rep...@bugs.python.org http://bugs.python.org/issue13971 ___ ___ Python-bugs-list mailing list Unsubscribe: http://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
