umedoblock added the comment:
I don't agree with "not a bug".
>>> s1, v1, ndigits1 = "1.65", 1.65, 1
>>> s2, v2, ndigits2 = "2.675", 2.675, 2
>>> decimal.Decimal(v1)
Decimal('1.649999999999999911182158029987476766109466552734375')
>>> round(v1, ndigits1)
1.6
>>> round(decimal.Decimal(s1), ndigits1)
Decimal('1.6') # EQUAL expression round(v1, ndigits1)
>>> decimal.Decimal(v2)
Decimal('2.67499999999999982236431605997495353221893310546875')
>>> round(v2, ndigits2)
2.67
>>> round(decimal.Decimal(s2), ndigits2)
Decimal('2.68') # DIFFERENT expression round(v2, ndigits2)
decimal module should give me different expression about below.
round(decimal.Decimal(s1), ndigits1) and round(v1, ndigits1).
BECAUSE
round(decimal.Decimal(s2), ndigits2) and round(v2, ndigits2)
give me DIFFERENT expression.
----------
title: round(1.65, 1) return 1.6 with decimal -> round(1.65, 1) return 1.6 with
decima modulel
_______________________________________
Python tracker <rep...@bugs.python.org>
<http://bugs.python.org/issue24827>
_______________________________________
_______________________________________________
Python-bugs-list mailing list
Unsubscribe:
https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
