[issue28536] Show the qualified name when a call fails

2018-07-26 Thread Berker Peksag 


Change by Berker Peksag :


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stage:  -> resolved
status: open -> closed
type:  -> enhancement

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[issue28536] Show the qualified name when a call fails

2016-10-25 Thread Martin Panter 

Martin Panter added the comment:

Perhaps you should merge your work with Issue 2786. With a very brief look, the 
patches seem to take a similar approach.

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nosy: +martin.panter
resolution:  -> duplicate
superseder:  -> Names in function call exception should have class names, if 
they're methods

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[issue28536] Show the qualified name when a call fails

2016-10-25 Thread Ryan Gonzalez 

Ryan Gonzalez added the comment:

HAHA, I lied. :D Attached is what I have so far.

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keywords: +patch
Added file: 
http://bugs.python.org/file45225/0001-Make-failed-calls-to-methods-show-the-fully-qualifie.patch

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[issue28536] Show the qualified name when a call fails

2016-10-25 Thread Ryan Gonzalez 

New submission from Ryan Gonzalez:

e.g. make this:


class X:
def __init__(self): pass

X(1)


print something like this:


TypeError: X.__init__() takes 1 positional argument but 2 were given


instead of:


TypeError: __init__() takes 1 positional argument but 2 were given


I'm trying to see if I can create a patch right now, though it probably won't 
be ready until Thursday.

--
components: Interpreter Core
messages: 279460
nosy: Ryan.Gonzalez
priority: normal
severity: normal
status: open
title: Show the qualified name when a call fails
versions: Python 3.7

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