Mark Dickinson added the comment:
The result is correct. Note that the first character is "0", which is chr(48).
>>> '0' == '\x30'
True
>>> '0\x11\x00\x00' == '\x30\x11\x00\x00'
True
--
nosy: +mark.dickinson
resolution: -> not a bug
stage: -> resolved
status: open -> closed
New submission from jimmy :
The result of variable "a" should be b'30\x11\x00\x00' not b'0\x11\x00\x00' .
>>> import struct
>>> a = struct.pack(">> print(a)
b'0\x11\x00\x00'
>>>
--
messages: 328794
nosy: jimmy
priority: normal
severity: normal
status: open
title: Struct pack()
