Pascal Chambon chambon.pas...@gmail.com added the comment:
Thansk a lot for reviewing the problem
Indeed, p.wait() seems to do the trick in this case.
Is there any global way to avoid such pipe problems ? I mean, in any
case, one end of each pipe has to be closed before the other end, so
such
Hirokazu Yamamoto ocean-c...@m2.ccsnet.ne.jp added the comment:
Probably this happens because receiever.py doesn't wait for flooder.py
termination, and pipe end is closed when recieiver.py terminates.
Does this code work for you?
p = subprocess.Popen(python
Hirokazu Yamamoto ocean-c...@m2.ccsnet.ne.jp added the comment:
This happens because when flooder.py terminates, its stdout will be
closed, but another pipe end in receirver.py process is already closed, so
Python\sysmodule.c(1098): _check_and_flush (FILE *stream)
In this function, fflush()
New submission from Pascal Chambon [EMAIL PROTECTED]:
I've created on my desktop a file flooder.py containing just the following:
##
import sys, os
progress=open(rC:\Users\v-pascha\Desktop\STDERR.txt,w)
for i in range(101):
print str(i)*20
progress.write( str(i)+\n )
