Georg Brandl ge...@python.org added the comment:
There is no way for the interpreter to distinguish between builtins and
other types of free variables.
If you need unqualified exec to work in an innner function, use function
parameters with defaults, like this:
def a():
def b(long=long):
Martin v. Löwis [EMAIL PROTECTED] added the comment:
There is no proposed patch yet, so this is out of scope for 2.5.3.
--
nosy: +loewis
versions: -Python 2.5.3
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Python tracker [EMAIL PROTECTED]
http://bugs.python.org/issue4220
Terry J. Reedy [EMAIL PROTECTED] added the comment:
The request as stated is invalid.
'Int' and 'long' are built-in names, not keywords.
The context of the cited sentence is
If a name is bound in a block, it is a local variable of that block,
unless declared as nonlocal. If a name is bound at
Changes by Terry J. Reedy [EMAIL PROTECTED]:
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versions: +Python 3.0
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Python tracker [EMAIL PROTECTED]
http://bugs.python.org/issue4220
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Python-bugs-list
New submission from David Fugate [EMAIL PROTECTED]:
#--
VERSION AFFECTED: 2.5 and 2.6
BUILD TYPE: x86
FLAGS PASSED TO PYTHON.EXE: None
OPERATING SYSTEM: 32-bit Windows Vista SP1
Changes by Alexander Belopolsky [EMAIL PROTECTED]:
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nosy: +belopolsky
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Python tracker [EMAIL PROTECTED]
http://bugs.python.org/issue4220
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Python-bugs-list
