[issue8626] TypeError: rsplit() takes no keyword arguments

2011-01-01 Thread Sandro Tosi
Sandro Tosi sandro.t...@gmail.com added the comment: That's interesting: do we have a place where we explain how to read the doc? I mean, a place were we can provide example/explain how we write docs, so f.e.: str.rsplit([sep[, maxsplit]]) is a description for a method that could accept 2

[issue8626] TypeError: rsplit() takes no keyword arguments

2011-01-01 Thread Éric Araujo
Éric Araujo mer...@netwok.org added the comment: The description for the function directive is at http://docs.python.org/dev/documenting/markup.html However, I’m not sure whether the doc is accurate, since there was a switch from spam([style]) to spam(style=None) some time ago, for example

[issue8626] TypeError: rsplit() takes no keyword arguments

2010-05-05 Thread Dave Abrahams
New submission from Dave Abrahams d...@boostpro.com: Based on the rsplit documentation, I'd expect 'foo bar'.rsplit(maxsplit=1) to work. This is probably a much bigger problem than just rsplit, i.e. I doubt there is a policy about whether documented parameter names need to be usable as

[issue8626] TypeError: rsplit() takes no keyword arguments

2010-05-05 Thread Brett Cannon
Changes by Brett Cannon br...@python.org: -- keywords: +easy stage: - unit test needed ___ Python tracker rep...@bugs.python.org http://bugs.python.org/issue8626 ___ ___

[issue8626] TypeError: rsplit() takes no keyword arguments

2010-05-05 Thread Antoine Pitrou
Antoine Pitrou pit...@free.fr added the comment: This is more of a documentation issue than anything else. The fact that the argument is named maxsplit and accepts a default value doesn't mean it's usable as a keyword argument. It would be difficult to document a parameter without giving it a