On 27/05/2014 13:44, Tal Einat wrote:
On Tue, May 27, 2014 at 2:45 PM, Michael Urman wrote:
On Tue, May 27, 2014 at 4:05 AM, Chris Angelico wrote:
On Tue, May 27, 2014 at 6:58 PM, Serhiy Storchaka wrote:
26.05.14 10:59, raymond.hettinger написав(ла):
+result = [(elem, i) for i, el
On May 27, 2014, at 1:58 AM, Serhiy Storchaka wrote:
> Perhaps it is worth to add simple comment explaining why this is not
> equivalent to just list(zip(it, range(n))). Otherwise it can be
> unintentionally "optimized" in future.
FWIW, that is covered by the test cases.
If you substitute lis
On 27.05.2014 11:05, Chris Angelico wrote:
> On Tue, May 27, 2014 at 6:58 PM, Serhiy Storchaka wrote:
>> 26.05.14 10:59, raymond.hettinger написав(ла):
>>>
>>> +result = [(elem, i) for i, elem in zip(range(n), it)]
>>
>>
>> Perhaps it is worth to add simple comment explaining why this is n
On Tue, May 27, 2014 at 2:45 PM, Michael Urman wrote:
> On Tue, May 27, 2014 at 4:05 AM, Chris Angelico wrote:
>> On Tue, May 27, 2014 at 6:58 PM, Serhiy Storchaka
>> wrote:
>>> 26.05.14 10:59, raymond.hettinger написав(ла):
+result = [(elem, i) for i, elem in zip(range(n), it
On Tue, May 27, 2014 at 4:05 AM, Chris Angelico wrote:
> On Tue, May 27, 2014 at 6:58 PM, Serhiy Storchaka wrote:
>> 26.05.14 10:59, raymond.hettinger написав(ла):
>>>
>>> +result = [(elem, i) for i, elem in zip(range(n), it)]
>>
>>
>> Perhaps it is worth to add simple comment explaining
On Tue, May 27, 2014 at 6:58 PM, Serhiy Storchaka wrote:
> 26.05.14 10:59, raymond.hettinger написав(ла):
>>
>> +result = [(elem, i) for i, elem in zip(range(n), it)]
>
>
> Perhaps it is worth to add simple comment explaining why this is not
> equivalent to just list(zip(it, range(n))). Ot
26.05.14 10:59, raymond.hettinger написав(ла):
+result = [(elem, i) for i, elem in zip(range(n), it)]
Perhaps it is worth to add simple comment explaining why this is not
equivalent to just list(zip(it, range(n))). Otherwise it can be
unintentionally "optimized" in future.