Re: [Python-Dev] pycapsule:PyObject * is NULL pointer

hi @MRAB i try again，it not ok. test files: 1.cpython.cpp ---c call python maintenance.py 2.maintenance.py python maintenance.py call pycapsule.cpp(dll) the code file,see attachment. At 2018-02-21 11:18:18, "MRAB" wrote: >On 2018-02-21 02:28, 赵亚 wrote: > >This "

[Python-Dev] void* from c to python and to c？

I have a demand: c call python ,have a void* pointer pass to python and python call c,the void* pointer need pass to c. i don't know how to do，have any good idea ？ thanks！___ Python-Dev mailing list Python-Dev@python.org https://mail.python.org/mailman/

[Python-Dev] pycapsule:PyObject * is NULL pointer

i have question:call,c-->python-->c. 1.the c pointer void* abc="123" by pycapsule in the c code. .. void* lpContext = "abc"; PyObject * lpPyContext = PyCapsule_New(lpContext, "Context",NULL); .. PyTuple_SetItem(pArgs, 1, lpPyContext); PyObject* pyResult = PyObject_CallObject(pFunc, pArgs);