Perhaps use the id of an object instead of its value. Here's how it might
work
>>> store = {}
>>> def wibble(fn):
... val = fn()
... name = fn.__name__
... store[id(val)] = name
... return val
>>> @wibble
... def ddd():
... return tuple(range(4))
>>> ddd
(0, 1, 2, 3)
POSTSCRIPT
We can also use locals() to 'inverse search' to get the name, much as in
the original post.
>>> locals()['x']
(0, 1, 2, 3)
>>> id(x)
139910226553296
>>> id(locals()['x'])
139910226553296
--
Jonathan
___
Python-ideas mailing list -- python-id
Jonathan Fine writes:
> We can also use locals() to 'inverse search' to get the name, much
> as in the original post.
As has already been explained, locals() (and any namespace for that
matter) is a many-one mapping, and therefore the inverse is not
well-defined.
At least for the 'print(f"coun
Good ideas, however not robust:
a = 1
b = 1
print(id(a))# 4536318072
print(id(b))# 4536318072
> On 14 Sep 2023, at 16:35, Jonathan Fine wrote:
>
> POSTSCRIPT
>
> We can also use locals() to 'inverse search' to get the name, much as in the
> original post.
>
> >>> locals()['x']
> (0, 1
