On Thu, Apr 30, 2009 at 08:32:31AM +0200, Jeroen Ruigrok van der Werven wrote:
-On [20090430 02:21], Dale Amon (a...@vnl.com) wrote:
import sys
sys.path.extend (['../lib', '../bin'])
from VLMLegacy.CardReader import CardReader
rdr = CardReader (../example/B767.dat,PRINTABLE)
iotypes
On Thu, Apr 30, 2009 at 02:38:03AM -0400, Dave Angel wrote:
As Scott David Daniels says, you have two built-in choices, depending on
Python version. If you can use __import__(), then realize that
mod = __import__(WINGTL)
will do an import, using a string as the import name. I don' t
On Thu, Apr 30, 2009 at 04:33:57AM -0300, Gabriel Genellina wrote:
En Thu, 30 Apr 2009 03:04:40 -0300, alex23 wuwe...@gmail.com escribió:
Are you familiar with __import__?
iotypes = [WINGTL,VLMPC,VLM4997]
for iotype in iotypes:
packagename = VLMLegacy. + iotype + .Conditions
classname
Gabriel gave me the key to a fine solution, so
just to put a bow tie on this thread:
#!/usr/bin/python
import sys
sys.path.extend (['../lib', '../bin'])
from VLMLegacy.CardReader import CardReader
rdr = CardReader (../example/B767.dat,PRINTABLE)
iotypes = [WINGTL,VLMPC,VLM4997]
for iotype
I am going around in circles right now and have to
admit I do not understand what is going on with
import of hierarchical packages/modules. Perhaps someone
can get me on the road again. Here is a subset of what I
am trying to accomplish:
The package directory set up:
VLMLegacy/
I am trying to get to the heart of what it is I am
missing. Is it the case that if you have a module C in a
package A:
A.C
that there is no way to load it such that you can use:
x = A.C()
in your code? This is just a simpler case of what I'm
trying to do now, which has a
On Wed, Apr 29, 2009 at 01:12:33PM -0700, Scott David Daniels wrote:
Dale Amon wrote:
I am trying to get to the heart of what it is I am
missing. Is it the case that if you have a module C in a package A:
A.C
that there is no way to load it such that you can use:
x = A.C()
in your
On Wed, Apr 29, 2009 at 04:34:03PM -0400, Dale Amon wrote:
type = VLM4997
type.Header(args)
type.Plan(args)
type.Conditions(args)
Where the type might change from execution to execution
or even on different iterations.
Actually let me make that reflect more
On Wed, Apr 29, 2009 at 03:06:13PM -0700, Scott David Daniels wrote:
You did not answer the question above, and I think the answer is the root
of your misunderstanding. A class and a module are _not_the_same_thing_.
sys is not a package, it is a module.
Just because you put a class inside a
Well, I've managed to get close to what I want,
and just so you can see:
#!/usr/bin/python
import sys
sys.path.extend (['../lib', '../bin'])
from VLMLegacy.CardReader import CardReader
rdr = CardReader (../example/B767.dat,PRINTABLE)
iotypes = [WINGTL,VLMPC,VLM4997]
for iotype in iotypes:
On Wed, Apr 29, 2009 at 04:06:23PM -0700, Scott David Daniels wrote:
Dale Amon wrote:
The point I take away from this is that packages and
modules have dotted names, but Classes do not and there
is no way to do exactly what I wanted to do.
Nope. You have not been clear with what you
On Wed, Apr 29, 2009 at 10:02:46PM -0400, Dave Angel wrote:
The dot syntax works very
predictably, and quite flexibly. The problem was that by using the same
name for module and class, you didn't realize you needed to include both.
It is one of the hazards of working in many very
This finds nothing:
import re
import string
card = abcdef
DEC029 = re.compile([^0-9A-Z/ $*,.\-:#@'=\[(+\^!);\\\]%_?])
errs = DEC029.findall(card.strip(\n\r))
print errs
This works correctly:
import re
import string
card = abcdef
DEC029 = re.compile([^0-9A-Z/
There are a number of things which I have been used
to doing in other OO languages which I have not yet
figured out how to do in Python, the most important
of which is passing method names as args and inserting
them into method calls. Here are two cases I have been
trying to figure out for a
On Wed, Apr 08, 2009 at 09:03:00PM +0200, paul wrote:
I'd say you can use:
Thanks. I could hardly ask for a faster response on a
HowTo than this!
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On Mon, Mar 30, 2009 at 10:54:56PM -0700, Niklas Norrthon wrote:
I make sure my scripts are on the form:
# imports
# global initialization (not depending on sys.argv)
def main():
# initialization (might depend on sys.argv)
# script logic
# other functions
if __name__ ==
Just in case anyone else finds it useful, to be precise I use:
if opts.man:
p1 = Popen([echo, __doc__], stdout=PIPE)
p2 = Popen([pod2man], stdin=p1.stdout, stdout=PIPE)
p3 = Popen([nroff,-man], stdin=p2.stdout, stdout=PIPE)
output =
I wonder if someone could point me at documentation
on how to debug some of the standard Unix type things
in Idle. I cannot seem to figure out how to set my
argument line for the program I am debugging in an Idle
window. for example:
vlmdeckcheck.py --strict --debug file.dat
There must
On Mon, Mar 30, 2009 at 08:11:10PM -0500, Dave Angel wrote:
I don't know what Idle has to do with it. sys.args contains the command
line arguments used to start a script.
Dale Amon wrote:
I wonder if someone could point me at documentation on how to debug
some of the standard Unix type
On Mon, Mar 30, 2009 at 09:47:24PM -0500, Dave Angel wrote:
See http://docs.python.org/library/idle.html and search for command line
According to that page (for Python 2.6.1), you can set those parameters
on the command line that starts IDLE itself.
I haven't tried it yet, as I'm using
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