I really don't understand the following behavior:
class C(object):
... def __init__(self, s): self.s = s
... def __str__(self): return self.s
...
cafe = unicode(Caf\xe9, Latin-1)
c = C(cafe)
print Print using c.s:, c.s
Print using c.s: Café
print Print using just c:, c
Print
Gary Herron wrote:
Gerard Brunick wrote:
I really don't understand the following behavior:
class C(object):
... def __init__(self, s): self.s = s
... def __str__(self): return self.s
...
cafe = unicode(Caf\xe9, Latin-1)
c = C(cafe)
print Print using c.s:, c.s
Print using
Is there a way to do:
s = I like python %i%s of the time.
print s % (99, %)
without having to pass in %?
Thanks,
Gerard
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Consider: A)
class C(object):
... pass
...
def f(*args):
... print args
...
C.f = f
C.f
unbound method C.f
c=C()
c.f()
(__main__.C object at 0x04A51170,)
And B)
del c
C.f = types.MethodType(f, None, C)
C.f
unbound method C.f
c = C()
c.f()
(__main__.C object at
I can't solve your problem, but I can at least explain why I think its
hard. foo doesn't have any closed over
variables. Some of its locals have to live in cells, so that pre and
post can see them in their closures.
foo.func_code.co_cellvars
('x', 'y')
Now the only way that I know of to
Consider:
### Function closure example
def outer(s):
... def inner():
... print s
... return inner
...
f = outer(5)
f()
5
dir(f)
['__call__', '__class__', '__delattr__', '__dict__', '__doc__',
'__get__', '__getattribute__', '__hash__', '__init__', '__module__',
Consider:
def negate(func):
... def wrapper(*args, **kwargs):
... return not func(*args, **kwargs)
... return wrapper
...
def f(x):
... return x 10
...
g = negate(f)
g(20)
False
g(5)
True
Now g has the argument signature of (*args, **kwargs). Pop-up help in
My way is ugly. These has to be a better way.
Thanks,
Gerard
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