On Wednesday, 11 September 2019 20:25:32 UTC+10, Sayth Renshaw wrote:
> On Wednesday, 11 September 2019 20:11:21 UTC+10, Sayth Renshaw wrote:
> > Hi
> >
> > I want to allow as many lists as needed to be passed into a function.
> > But how can I determine how man
On Wednesday, 11 September 2019 20:11:21 UTC+10, Sayth Renshaw wrote:
> Hi
>
> I want to allow as many lists as needed to be passed into a function.
> But how can I determine how many lists have been passed in?
>
> I expected this to return 3 but it only returned 1.
>
>
, matrix2))
def add(*matrix):
print(len(locals()))
add(matrix1,matrix2,matrix3)
Cheers
Sayth
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On Tuesday, 10 September 2019 12:56:36 UTC+10, Sayth Renshaw wrote:
> On Friday, 6 September 2019 07:52:56 UTC+10, Piet van Oostrum wrote:
> > Piet van Oostrum <> writes:
> >
> > > That would select ROWS 0,1,5,6,7, not columns.
> > > To select columns
-versus-copy
So tried this
df['c'] = df.apply(lambda df1: df1['Current Team'].str.lower().str.strip() ==
df1['New Team'].str.lower().str.strip(), axis=1)
Based on this SO answer https://stackoverflow.com/a/46570641
Thoughts?
Sayth
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That is actually consistent with Excel row, column. Can see why it works that
way then.
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On Sunday, 1 September 2019 10:48:54 UTC+10, Sayth Renshaw wrote:
> I've created a share doc same structure anon data from my google drive.
>
> https://drive.google.com/file/d/0B28JfFTPNr_lckxQRnFTRF9UTEFYRUVqRWxCNVd1VEZhcVNr/view?usp=sharing
>
> Sayth
I tried creating
can
> think of with Google but can't find why or how. Could you help me? Thanks.
>
> --
> YX. D.
Does this help?
https://stackoverflow.com/questions/4320761/importerror-no-module-named-winreg-python3
Sayth
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print("Publishing message to topic",
> "microscope/light_sheet_microscope/UI")
> client.publish("microscope/light_sheet_microscope/UI",
> device_message)
> time.sleep(2) # wait
> client.loop_stop() # stop the loop
>
> def closeEvent(self, event):
> self.close()
>
> test2.py
>
> from PyQt5 import QtCore, QtGui, QtWidgets
> import sys
> from PyQt5.QtWidgets import *
> from PyQt5.QtCore import *
> from PyQt5 import QtWidgets, uic
>
> class SubWindow(QWidget):
> def __init__(self, parent = None):
> super(SubWindow, self).__init__(parent)
> self.setMinimumSize(QSize(300, 250))
> label = QLabel("Sub Window", self)
>
> self.modeButton = QtWidgets.QPushButton("Click me",self)
> self.modeButton.setGeometry(QtCore.QRect(10, 40, 81, 23))
>
> self.modeButton.clicked.connect(self.modFun)
>
>
>
> def modFun(self):
> print("Hello there i'm Click me")
>
> def closeEvent(self, event):
> self.close()
>
> Thanks.
list_of_file_name = []
my_file = getGUIFilename()
list.append(my_file)
Sayth
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I've created a share doc same structure anon data from my google drive.
https://drive.google.com/file/d/0B28JfFTPNr_lckxQRnFTRF9UTEFYRUVqRWxCNVd1VEZhcVNr/view?usp=sharing
Sayth
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On Sunday, 1 September 2019 05:19:34 UTC+10, Piet van Oostrum wrote:
> Sayth Renshaw writes:
>
> > But on both occasions I receive this error.
> >
> > # KeyError: 'the label [Current Team] is not in the [index]'
> >
> > if I test df1 before tryi
.strip()
and
df1 = df[['UID','Name','New Leader','Current Team', 'New Team']].copy()
df1['Difference'] = df1.loc['Current Team'].str.lower().str.strip() ==
df1.loc['New Team'].str.lower().str.strip()
But on both occasions I receive this error.
# KeyError: 'the label [Current Team] is not in the [index]'
if I test df1 before trying to create the new column it works just fine.
Sayth
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On Thursday, 29 August 2019 20:33:46 UTC+10, Peter Otten wrote:
> Sayth Renshaw wrote:
>
> > will find the added
> > pairs, but ignore the removed ones. Is that what you want?
> >
> > Yes, I think. I want to find the changed pairs. The people that moved team
> &
'New Team')]
>
> Or maybe even make an explicit copy:
>
> df1 = df[['UID','Name','New Leader','Current Team', 'New Team']].copy()
Thank you so much.
Sayth
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will find the added
pairs, but ignore the removed ones. Is that what you want?
Yes, I think. I want to find the changed pairs. The people that moved team
numbers.
Sayth
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Try using .loc[row_indexer,col_indexer] = value instead
See the caveats in the documentation:
http://pandas.pydata.org/pandas-docs/stable/indexing.html#indexing-view-versus-copy
If I update the line to use loc as this I still receive a long error.
df1['Difference'] = df1.loc['Curren
On Thursday, 29 August 2019 14:03:44 UTC+10, Sayth Renshaw wrote:
> On Thursday, 29 August 2019 13:53:43 UTC+10, Sayth Renshaw wrote:
> > On Thursday, 29 August 2019 13:25:01 UTC+10, Sayth Renshaw wrote:
> > > Hi
> > >
> > > Trying to find whats changed in
On Thursday, 29 August 2019 13:53:43 UTC+10, Sayth Renshaw wrote:
> On Thursday, 29 August 2019 13:25:01 UTC+10, Sayth Renshaw wrote:
> > Hi
> >
> > Trying to find whats changed in this example. Based around work and team
> > reschuffles.
> >
> > So fi
On Thursday, 29 August 2019 13:25:01 UTC+10, Sayth Renshaw wrote:
> Hi
>
> Trying to find whats changed in this example. Based around work and team
> reschuffles.
>
> So first I created my current teams and then my shuffled teams.
>
> people = ["Tim","
>
> A site like http://www.pyregex.com/ allows you to check your regex with
> slightly fewer clicks and keystrokes than editing your program.
Thanks Jason
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attempting to compare for change.
[i for i, j in zip(teams, shuffle_teams) if i != j]
#Result
[('Tim', 1), ('Ally', 2), ('Fred', 3), ('Fredricka', 3)]
#Expecting to see
[('Fredricka', 1),('Tim', 2)]
What's a working way to go about this?
Sayth
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On Wednesday, 21 August 2019 03:16:01 UTC+10, Ian wrote:
> Or use the "pairwise" recipe from the itertools docs:
>
> from itertools import tee
>
> def pairwise(iterable):
> "s -> (s0,s1), (s1,s2), (s2, s3), ..."
> a, b = tee(iterable)
> next(b, None)
> return zip(a, b)
>
> for n
, 1.
But am receiving
TypeError: 'int' object is not subscriptable
Why?
Cheers
Sayth
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this?
>
>
>
> --
> Cecil Westerhof
Pandas may work out better.
import pandas as pd
df = pd.read_excel('spreadsheet')
# find the row by filtering with regex
df2 = df.'column'.str.contains('criteria as regex')
df2.pd.save_excel('output.xlsx')
Cheers
Sayth
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match 10.10.168.2[0-9]
>
> If someone out there knows a simple solution. I would love to see it.
> Thanks in advance.
> crzzy1
Not sure exactly what the input is but a comprehension would do this.
[x for x in input_line.split(' ') if == '10.10.168.2']
Cheers
Sayth
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9-06-22 10:00:00 Doe, John;#42;Robbins, Rita;
>
> [2 rows x 2 columns]
> Session date Consultant
> 0 2019-06-21 11:15:00 WNEWSKI, Joan
> 1 2019-06-21 11:15:00BALIN, Jock
> 2 2019-06-21 11:15:00DUNE, Colem
> 3 2019-06-22 10:00:00 Doe, John
> 4 2019-06-22 10:00:00 Robbins, Rita
>
> [5 rows x 2 columns]
> $
Mind a little blown :-). Going to have to play and break this several times to
fully get it.
Thanks
Sayth
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t']].str.contains(r'/\b[^\d\W]+\b/g')
neither option works as the column is a list.
Thanks
Sayth
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['Consultant'] =
completed_tasks['Consultant'].str.contains(pattern)
...
Works without the regex which causes this error AttributeError: Can only use
.str accessor with string values, which use np.object_ dtype
pattern = "\\#d"
completed_tasks['Consultant'] = completed_tasks['Consultant'].str.split(pat =
";")
Sayth
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consultants name?
NB. There are varied amounts of consultants so splitting across columns is
uneven. if it was even melt seems like it would be good
https://dfrieds.com/data-analysis/melt-unpivot-python-pandas
Thanks
Sayth
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ager:
>
> from itertools import islice
> from contextlib import contextmanager
>
> infile = ...
> outfile = ...
>
> @contextmanager
> def head(infile, numlines):
> with open(infile) as f:
> yield islice(f, numlines)
>
> with open(outfile, "w
with open(infile, 'r+') as f:
lines_gen = islice(f, lineNum)
yield lines_gen
for line in getWord(fileName, 5):
with open(dumpName, 'a') as f:
f.write(line)
Thanks,
Sayth
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it could be very important so then async await might be
an option.
Sayth
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On Friday, 19 April 2019 17:01:33 UTC+10, Sayth Renshaw wrote:
> Set the first item in the list as the current largest.
> Compare each subsequent integer to the first.
> if this element is larger, set integer.
def maxitwo(listarg):
myMax = listarg[0]
fo
Set the first item in the list as the current largest.
Compare each subsequent integer to the first.
if this element is larger, set integer.
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es the
first item and comparison continues.
Sayth
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> >
> It's still overly complicated.
>
This is where I have ended up. Without itertools and max its what I got
currently.
def maximum(listarg):
myMax = listarg[0]
for item in listarg:
for i in listarg[listarg.index(item)+1:len(listarg)]:
if myMax < i:
(items)]:
if myMax < i:
myMax = i
else:
pass
return myMax
if __name__ == "__main__":
print(maximum([4,3,6,2,1,4]))
Cheers
Sayth
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= []
if seq:
max_val = seq[0]
for i,val in ((i,val) for i,val in enumerate(seq) if val >= max_val):
if val == max_val:
max_indices.append(i)
else:
max_val = val
max_indices = [i]
return max_indices
This is probably the nicest one but still uses Max.
>>> a=[5,4,3,2,1]
>>> def eleMax(items, start=0, end=None):
... return max(items[start:end])
Thanks
Sayth
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fficult to be honest.
https://chrisyeh96.github.io/2017/08/08/definitive-guide-python-imports.html#example-directory-structure
Then there was this rather long list of traps.
http://python-notes.curiousefficiency.org/en/latest/python_concepts/import_traps.html
Most guides say it was fixed in 3.3 but still seems quite confusing post 3.3
Cheers
Sayth
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should work but doesn't.
Cheers
Sayth
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On Saturday, 6 April 2019 08:21:51 UTC+11, maak khan wrote:
> i need your help guys .. plz
With?
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, n-1), (s,)))
>
> fizzbuzz = map("".join, zip(make("Fizz", 3), make("Buzz", 5)))
>
> for i, fb in enumerate(islice(fizzbuzz, 100), 1):
> print(fb or i)
Thanks
Sayth
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: output += "Fizz"
if (num % 5 == 0): output += "Buzz"
print(output or num)
Haven't quite got it. But is possible nice and succinct like the javascript
version. Maybe lambda will do it, gonna try that.
Any unique mindlowing style FizzBuzz I would never have
On Thursday, 4 April 2019 10:51:35 UTC+11, Paul Rubin wrote:
> Sayth Renshaw writes:
> > for x in range ( max_root ):
> > 1) Do you see a memory bottleneck here? If so, what is it?
> > 2) Can you think of a way to fix the memory bottleneck?
>
> In Python 2, range(
. But is this the correct way to go? More of a am I thinking
correctly questino.
item = 0
while item < MAX:
print(supply_squares(item))
item += 1
Thanks
Sayth
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ame across a problem. "11st", "12nd", "13rd"?
>
> [snip]
> >
> > Output:
> >
> >>>> for day in range(1, 32):
> > print( nthSuffix(day))
> >
> > 1st
> > 2nd
> > 3rd
> > 4th
> > 5
uffix in mapping.items():
> if x in key:
> return suffix
> return "th"
>
> However, for big dictionaries (with many keys) you loose a key strength
> of dicts: constant time lookup. You can see the above code (and the
> earlier "if" code) are rather linear, with run time going up linearly
> with the number of keys. You're better with the int->string single value
> dict version.
>
> Cheers,
> Cameron Simpson
It seems odd with C having switch that its cleaner and more efficient than
python where we are having to implement our own functions to recreate switch
everytime.
Or perhaps use a 3rd party library like
https://github.com/mikeckennedy/python-switch
You have both given good options, it seems there are no standard approaches in
this case.
Cheers
Sayth
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t a function that uses a dictionary. Not sure how
to supply list into it to keep it brief and with default case of 'th'.
This is my current code.
def f(x):
return {
[1, 21, 31]: "st",
[2, 22]: "nd",
[3, 23]: "rd",
}.get(x, &quo
Sayth
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deas on how the function argument can be used as the search attribute?
Thanks
Sayth
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solve each small part, and
> (3) assemble the whole puzzle. This is a skill you must
> master. And it's really not difficult. It just requires a
> different way of thinking about tasks.
Thank you Rick, good advice. I really am enjoying coding at the moment, got
myself and life in a good headspace.
Cheers
Sayth
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ving to
figure out the structure each time. Just want to automate that part so I can
move through the munging part and spend more time on higher value tasks.
Cheers
Sayth
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on 3
import operator
def getFromDict(dataDict, mapList):
return reduce(operator.getitem, mapList, dataDict)
def setInDict(dataDict, mapList, value):
getFromDict(dataDict, mapList[:-1])[mapList[-1]] = value
Then get the values from the keys
>>> getFromDict(dataDict, ["a", "r"])
1
That would mean I could using my function if I get it write be able to feed it
any json, get all the full paths nicely printed and then feed it back to the SO
formula and get the values.
It would essentially self process itself and let me get a summary of all keys
and their data.
Thanks
Sayth
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On Tuesday, 24 July 2018 14:25:48 UTC+10, Rick Johnson wrote:
> Sayth Renshaw wrote:
>
> > elements = [['[{0}]'.format(element) for element in elements]for elements
> > in data]
>
> I would suggest you avoid list comprehensions until you master long-form
&g
On Tuesday, 24 July 2018 14:25:48 UTC+10, Rick Johnson wrote:
> Sayth Renshaw wrote:
>
> > elements = [['[{0}]'.format(element) for element in elements]for elements
> > in data]
>
> I would suggest you avoid list comprehensions until you master long-form
&g
lossary]', '[GlossDiv]', '[GlossList]'],
['[glossary]', '[GlossDiv]', '[GlossList]', '[GlossEntry]'],
.]
I used.
elements = [['[{0}]'.format(element) for element in elements]for elements in
data]
Is there a good way to s
out)
print(answer)
Think I need to bring it in a list not an element of a list and process it.
Cheers
Sayth
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ssDiv', 'GlossList', 'GlossEntry', 'GlossDef',
'GlossSeeAlso', 0],
['glossary', 'GlossDiv', 'GlossList', 'GlossEntry', 'GlossDef',
'GlossSeeAlso', 1],
['glossary', 'GlossDiv', 'GlossList', 'GlossEntry', 'GlossSee']]
I am trying to change it to be.
[['glossary'],
['glossary']['title'],
['glossary']['GlossDiv'],
]
Currently when I am formatting I am flattening the structure(accidentally).
for item in data:
for elem in item:
out = ("[{0}]").format(elem)
print(out)
Which gives
[glossary]
[title]
[GlossDiv]
[title]
[GlossList]
[GlossEntry]
[ID]
[SortAs]
[GlossTerm]
[Acronym]
[Abbrev]
[GlossDef]
[para]
[GlossSeeAlso]
[0]
[1]
[GlossSee]
Cheers
Sayth
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On Thursday, 26 April 2018 07:57:28 UTC+10, Paul Rubin wrote:
> Sayth Renshaw writes:
> > What I am trying to figure out is how I give myself surety that the
> > data I parse out is correct or will fail in an expected way.
>
> JSON is messier than people think. Here&#
sts = {}
>for n, item in enumerate(result):
># if this one is interested / not -filtered:
>print(n, item)
>runner_lists[n] = result[n]["RacingFormGuide"]["Event"]["Runners"]
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Sorry
figured it. Needed to use n to iterate when creating.
runner_lists = {}
for n, item in enumerate(result):
# if this one is interested / not -filtered:
print(n, item)
runner_lists[n] = result[n]["RacingFormGuide"]["Event"]["R
em in enumerate(result):
# if this one is interested / not -filtered:
print(n, item)
runner_lists[n] = result["RacingFormGuide"]["Event"]["Runners"]
## Produces
Traceback (most recent call last):
dict_keys(['RaceDay', 'ErrorInfo', 'Success'])
File "/home/sayth/PycharmProjects/ubet_api_mongo/parse_json.py", line 31, in
runner_lists[n] = result["RacingFormGuide"]["Event"]["Runners"]
TypeError: list indices must be integers or slices, not str
Cheers
Sayth
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e noise.
>
>
>
>
> --
> Steve
> “Cheer up,” they said, “things could be worse.” So I cheered up, and sure
> enough, things got worse.
https://stackoverflow.com/a/18601429
Version mismatch between sqlite CLI and python sqlite API? I created again my
db from the script ins
gt;import json
> >from pprint import pprint
> >
> >with open(r'/home/sayth/Projects/results/Canterbury_2017-01-20.json', 'rb')
> >as f, open('socks3.json','w') as outfile:
> >to_read = json.load(f)
> [...]
> >me
Hi
I want to get a result from a largish json api. One section of the json
structure returns lists of data. I am wanting to get each resulting list
returned.
This is my code.
import json
from pprint import pprint
with open(r'/home/sayth/Projects/results/Canterbury_2017-01-20.json'
IX paths don't apply to your file
> system, and...
>
> > OSError: [Errno 22] Invalid argument:
> > 'C:\\Users\\Sayth\\Projects\\results/Warwick Farm2017-09-06T00:00:00.json'
>
> ... the colon is invalid on Windows file systems. You'll have to
> replace those
= r.json()
if data["RaceDay"] is not None:
file_name = data["RaceDay"]["Meetings"][0]["VenueName"] +
data["RaceDay"]["MeetingDate"] + '.json'
result_path = pathlib.PurePosixPath(r'C:\Users\Sa
On Thursday, 5 October 2017 15:13:43 UTC+11, Sayth Renshaw wrote:
> HI
>
> Looking for suggestions around json libraries. with Python. I am looking for
> suggestions around a long term solution to store and query json documents
> across many files.
>
> I will be
://objectpath.org/reference.html
Looking to leverage your experience.
Cheers
Sayth
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Thank you it was data["RaceDay"] that was needed.
ata = r.json()
if data["RaceDay"] is None:
print("Nothing here")
else:
print(data["RaceDay"])
Nothing here
Nothing here
Nothing here
{'MeetingDate': '2017-01-11T00:0
print(data["RaceDay"])
and I get output of
None
None
{'MeetingDate': '2017-01- ... and so on.
How can I actually get this to check?
If i use type(data) I also get None.
Cheers
Sayth
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> >
> > Thanks Thomas yes you are right with append. I have tried it but just
> > can't get it yet as append takes only 1 argument and I wish to give it 3.
> >
> You have not showed us what you tried, but you are probably missing a pair
> of brackets.
>
> C:\Users\User>python
> Python 3.6.0 (v
On Thursday, 21 September 2017 20:31:28 UTC+10, Thomas Jollans wrote:
> On 2017-09-21 12:18, Sayth Renshaw wrote:
> > This is my closest code
> >
> > data = r.json()
> >
> > raceData = []
> >
> > for item in data["RaceDay"]['Meeting
this
[('CLASS 3 HANDICAP', 1, 1000), ('BM 90 HANDICAP', 2, 1600), ('HERITAGE
STAKES', 3, 1100), ('BILL RITCHIE HANDICAP', 4, 1400), ('TEA ROSE STAKES', 5,
1400), ('GEORGE MAIN STAKES', 6, 1600), ('THE SHORTS', 7, 1100), ('KINGTON TOWN
STAKES', 8, 2000), ('BM 84 HANDICAP', 9, 1200)]
I get close creating a list of elements but each attempt I try to create the
list of tuples fails.
This is my closest code
data = r.json()
raceData = []
for item in data["RaceDay"]['Meetings'][0]['Races']:
raceDetails = item['RacingFormGuide']['Event']['Race']
raceData +=
(raceDetails['Name'],raceDetails['Number'],raceDetails['Distance'])
print(raceDetails)
which returns
['CLASS 3 HANDICAP', 1, 1000, 'BM 90 HANDICAP', 2, 1600, 'HERITAGE STAKES', 3,
1100, 'BILL RITCHIE HANDICAP', 4, 1400, 'TEA ROSE STAKES', 5, 1400, 'GEORGE
MAIN STAKES', 6, 1600, 'THE SHORTS', 7, 1100, 'KINGTON TOWN STAKES', 8, 2000,
'BM 84 HANDICAP', 9, 1200]
How do I get the tuples?
Cheers
Sayth
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itt")
> > 15 print(frog.ftype)
> > 16 print(frog.word)
> >
> > NameError: name 'frog' is not defined
> >
> > what exactly am I doing wrong?
>
> The if __name__ == "__main__" block is inside the class declaration
> block, so at the point that it runs the class has not been created
> yet. Try removing the indentation to place it after the class block
> instead.
Thank you that had me bugged I just couldn't see it.
Cheers
Sayth
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5 self.word = ftype
in frog()
12
13 if __name__ == "__main__":
---> 14 tree_frog = frog("Tree Frog", "Ribbitt")
15 print(frog.ftype)
16 print(frog.word)
NameError: name 'frog' is not defined
what exactly am I doing wrong?
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Sayth
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>>> after = sorted(before, key=lambda x: x == 0 and type(x) == int)
it is really good, however I don't understand it enough to reimplement
something like that myself yet.
Though I can that lambda tests for 0 that is equal to an int why does sorted
put them to the end?
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Sayth
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On Friday, 7 July 2017 12:46:51 UTC+10, Rick Johnson wrote:
> On Thursday, July 6, 2017 at 9:29:29 PM UTC-5, Sayth Renshaw wrote:
> > I was trying to solve a problem and cannot determine how to filter 0's but
> > not false.
> >
> > Given a list like this
> &g
, 1, 1, 3, [], 1, 9, {}, 9, 0, 0, 0, False, 0, 0, 0,
0, 0, 0, 0]
I have tried or conditions of v == False etc but then the 0's being false also
aren't moved. How can you check this at once?
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# note there are no implicit arguments like `base` in your code
for _ in range(numdays):
yield first
first += ONE_DAY
Thanks
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then:
# open a file for writing using url paramters
with open(SR + DAY + MONTH + YEAR + '.json', 'w') as f:
# Do stuff from here not relevant to question.
I have just gotten lost.
Is there an easier way to go about this?
Cheers
Sayth
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25, 23, 58, 11),
> datetime.datetime(2017, 12, 27, 23, 58, 11)])
>
> In [45]:
Thanks. I am just researching now the format that has come out. unclear what 58
represents.
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Sayth
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https://docs.python.org/2/library/calendar.html#calendar.Calendar.itermonthdays
In [20]: calendar.setfirstweekday(calendar.SATURDAY)
In [21]: calendar.firstweekday()
Out[21]: 5
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Sayth
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ry it?
Also checked out Python Arrow http://arrow.readthedocs.io/en/latest/ as it
expands on the python standard library but I couldn't find an obvious example
of this.
Thoughts or examples?
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Sayth
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gt;> find_it(test_seq)
But what may be the smallest thing in this i had no idea I could do [result] =
blah and get a generator on the return variable that seems insane.
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Sayth
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ther adding to a set or removing from
> it. At the end, your set should contain exactly one element. I'll let
> you write the actual code :)
>
> ChrisA
ChrisA the way it sounds through the list is like filter with map and a lambda.
http://www.python-course.eu/lambda.php Hav
appearing an
odd number of times given that is there a neater way to get the answer?
Thanks
Sayth
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27;, 'Machinegun Jubs', '6', '53', '77', '6', '2', '1', '1 $71685.00']
> ['46295', 'Zara Bay', '1', '53', '77', '12', '2', '3', '3 $112645.00']
I went for the one I can understand which was inplace
def flatten_inplace(rows, index):
for row in rows:
row[index:index + 1] = row[index]
return rows
See now if I can make it more adaptable to use it in some other situations,
quite useful.
Thanks
Sayth
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#x27;, '53', '77', '6', '2', '1', '1 $71685.00'],
['46295', 'Zara Bay', '1', '53', '77', '12', '2', '3', '3 $112645.00']]
Been looking around but most solutions just entirely flatten everything.
This was popular on SO but yeah it flattens everything I want to be more
selective
def flatten(lst):
for elem in lst:
if type(elem) in (tuple, list):
for i in flatten(elem):
yield i
else:
yield elem
What I am thinking is that if for each list the sublist should be at index 1, so
[0][1]
[1][1]
[2][1]
for item in list:
item[1] - somehow flatten.
Thoughts?
Sayth
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lt for PyXB and generateDS
(https://pythonhosted.org/generateDS/).
Both seem to be libraries for generating bindings to structures for parsing so
maybe I am searching the wrong thing. What is the right thing to search?
Cheers
Sayth
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race_writer = csv.writer(csvf, delimiter=','
)
thanks for your time and assistance. It's much appreciated
Sayth
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x27;) as csvf:
for file in rootobs:
# create and write csv
Sayth
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")
with open(write_to, 'w', newline='') as csvf:
for file in rootobs:
# create and write csv
Cheers
Sayth
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On Wednesday, 4 January 2017 12:36:10 UTC+11, Sayth Renshaw wrote:
> So can I call the generator twice and receive the same file twice in 2 for
loops?
>
> Once to get the files name and the second to process?
>
> for file in rootobs:
> base = os.path.
It definitely has more features than i knew http://xmlsoft.org/xmllint.html
Essentially thigh it appears to be aimed at checking validity and compliance of
xml.
I why to check the structure of 1 xml file against the previous known structure
to ensure there are no changes.
Cheers
Sayth
lt for PyXB and generateDS
(https://pythonhosted.org/generateDS/).
Both seem to be libraries for generating bindings to structures for parsing so
maybe I am searching the wrong thing. What is the right thing to search?
Cheers
Sayth
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race_writer = csv.writer(csvf, delimiter=','
)
thanks for your time and assistance. It's much appreciated
Sayth
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newline='') as csvf:
for file in rootobs:
# create and write csv
Sayth
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On Wednesday, 4 January 2017 12:36:10 UTC+11, Sayth Renshaw wrote:
> So can I call the generator twice and receive the same file twice in 2 for
> loops?
>
> Once to get the files name and the second to process?
>
> for file in rootobs:
> base = os.pa
quot;)
with open(write_to, 'w', newline='') as csvf:
for file in rootobs:
# create and write csv
Cheers
Sayth
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