Re: Multiple assignment and the expression on the right side

Alex Martelli wrote: > Suresh Jeevanandam <[EMAIL PROTECTED]> wrote: > >> Dear all, >> I read in "Python in a Nutshell" that when we have multiple assignments >> made on a single line, it is equivalent to have those many simple >> assignments

Mutable numbers

# I am new to python. In python all numbers are immutable. This means there is one object ( a region in the memory ) created every time we do an numeric operation. I hope there should have been some good reasons why it was designed this way. But why not have mutable numbers also in the language

Re: Augmented assignment

Thanks Alex. I was not aware of mtimeit. regards, Suresh Alex Martelli wrote: > Suresh Jeevanandam <[EMAIL PROTECTED]> wrote: > >> Hi, >> Is there any gain in performance because of augmented assignments. >> >> x += 1 vs x = x+1 >> >>

Augmented assignment

Hi, Is there any gain in performance because of augmented assignments. x += 1 vs x = x+1 Or are both of them the same. regards, Suresh -- http://mail.python.org/mailman/listinfo/python-list

Multiple assignment and the expression on the right side

Dear all, I read in "Python in a Nutshell" that when we have multiple assignments made on a single line, it is equivalent to have those many simple assignments and that the right side is evaluated once for each assignment. [The wordings are mine. I am not sure if this is what he intende

Re: mapping functions and lambda

I got it: dict([k.split('=') for k in s.split(',')]) regards, Suresh Suresh Jeevanandam wrote: > Given a string > s = 'a=1,b=2' > > I want to create a dictionary {'a': '1', 'b': '2'} > > I did, > >

mapping functions and lambda

Given a string s = 'a=1,b=2' I want to create a dictionary {'a': '1', 'b': '2'} I did, dict(map(lambda k: k.split('='), s.split(','))) Is it possible to get rid of the lambda here, without having to define another function just for this. Is this the easiest/straight-forward way to do this? r

finding the intersection of a list of Sets

I have a list of sets in variable lsets . Now I want to find the intersection of all the sets. r = lsets[0] for s in r[0:]: r = r & s Is there any other shorter way? Thanks in advance, Suresh -- http://mail.python.org/mailman/listinfo/python-list

Finding the relative path of a file from a dir

Hi, a = '/home/suresh/doc/html/a1/' b = '/home/suresh/doc/' I am looking for a standard function which will return the location of b relative to a i.e. '../..' I have gone through the os and os.path modules, but could not find any function of use. Should I write my own?

Re: parsing engineering symbols

Exactly what I wanted. It would be nice if the standard float function takes care of these. regards, Suresh > how about: > > SI_prefixes = { > 'Y':24, 'Z':21, 'E':18, 'P':15, 'T':12, 'G':9, 'M':6, 'k':3, > 'h':2, 'd':-1, 'c':-2, 'm':-3, u'\xb5':-6, 'u':-6, 'n':-9, 'p':-12, > 'f':-1

numarray :: multiplying all the elements in 1d array

Hi all, Lets say I have an array: from numarray import * a = array([ 6, 7, 8, 9, 10, 11, 12]) I want to multiply out all the elements and get the result. r = 1.0 for i in a: r = r*i Is there any faster, efficient

checking if a string contains a number

Hi, I have a string like, s1 = '12e3' s2 = 'junk' Now before converting these values to float, I want to check if they are valid numbers. s1.isdigit returns False. Is there any other function which would return True for s1 and False for s2. Than

parsing engineering symbols

Hi, I want to convert a string to float value. The string contains engineering symbols. For example, s = '12k' I want some function which would return 12000 function(s) => 12000.0 I searched the web, but could not fi