how about re.findall(r'\w+.=\W\D+(\d+)?',str) ?
this will work for any string within id !
~Ukanth
On Dec 21, 6:06 pm, Oltmans wrote:
> On Dec 21, 5:05 pm, Umakanth wrote:
>
> > How about re.findall(r'\d+(?:\.\d+)?',str)
>
> > extracts only numbers from
Ok. how about re.findall(r'\w+_(\d+)',str) ?
returns ['345343', '35343433', '8898', '8898'] !
On Dec 21, 6:06 pm, Oltmans wrote:
> On Dec 21, 5:05 pm, Umakanth wrote:
>
> > How about re.findall(r'\d+(?:\.\d+)?',str)
>
&
How about re.findall(r'\d+(?:\.\d+)?',str)
extracts only numbers from any string
~uk
On Dec 21, 4:38 pm, Oltmans wrote:
> Hello,. everyone.
>
> I've a string that looks something like
>
> lksjdfls kdjff lsdfs sdjfls = "amazon_35343433">sdfsdwelcome
>
>
> From above string I n
