Ok I think I got it:
PyObject* myFuncXXX(char* p_1, int p_2, char* p_3, int p_4)
{
int res;
char _host[255] = "";
int _port;
res = funcXXX(p_1, p_2, p_3, p_4, _host, &_port);
PyObject* res1 = PyInt_FromLong(res);
PyObject* res2 = PyString_FromStringAndSize(_host, strlen(_host));
Py
Hi i'm relatively new to Python and my C/C++ knowledge is near to
None. Having said that I feel justified to ask stupid questions :)
Ok now more seriously. I have question refering to char* used as
function parameters to return values. I have read SWIG manual to find
best way to overcome that, but
> Not in your code.
>
> Stefan
Not sure what you mean, but I tested and so far every document with
the same order of elements had number of comparisons equal to number
of nodes.
--
http://mail.python.org/mailman/listinfo/python-list
> If document order doesn't matter, try sorting the elements of each level in
> the two documents by some arbitrary deterministic key, such as (tag name,
> text, attr count, whatever), and then compare them in order, instead of trying
> to find matches in multiple passes. itertools.groupby() might
> off the top of my head (untested):
>
> >>> def equal(a, b):
> ... if a.tag != b.tag or a.attrib != b.attrib:
> ... return False
> ... if a.text != b.text or a.tail != b.tail:
> ... return False
> ... if len(a) != len(b):
> ... return False
> ... if any(not
On Jul 23, 6:29 pm, Stefan Behnel <[EMAIL PROTECTED]> wrote:
> Your requirements for a single Element are simple enough to write it in three
> to five lines of Python code (depending on your definition of equality).
> Checking this equality recursively is another two to three lines. Not complex
>
I'd like to know if there is any built in mechanism in lxml that lets
you check equality of two nodes from separate documents. I'd like it
to ignore attribute order and so on. It would be even better if there
was built in method for checking equality of whole documents (ignoring
document order). Pl
