On Apr 29, 2:46 pm, Julien [EMAIL PROTECTED] wrote:
Hi,
I'm fairly new in Python and I haven't used the regular expressions
enough to be able to achieve what I want.
I'd like to select terms in a string, so I can then do a search in my
database.
query = ' some words with and without
On Dec 11, 4:05 pm, Chris [EMAIL PROTECTED] wrote:
I'm trying to find the contents of an XML tag. Nothing fancy. I don't
care about parsing child tags or anything. I just want to get the raw
text. Here's my script:
import re
data =
?xml version='1.0'?
body
div class='default'
On May 25, 12:03 pm, sim.sim [EMAIL PROTECTED] wrote:
On 25 ÍÁÊ, 12:45, Marc 'BlackJack' Rintsch [EMAIL PROTECTED] wrote:
In [EMAIL PROTECTED], sim.sim wrote:
Below the code that tryes to parse an well-formed xml, but it fails
with error message:
not well-formed (invalid token): line
On May 22, 2:45 pm, sim.sim [EMAIL PROTECTED] wrote:
Hi all.
i'm faced to trouble using minidom:
#i have a string (xml) within CDATA section, and the section includes
\r\n:
iInStr = '?xml version=1.0?\nData![CDATA[BEGIN:VCALENDAR\r
\nEND:VCALENDAR\r\n]]/Data\n'
#After i create DOM-object,
On Mar 28, 10:51 am, Diez B. Roggisch [EMAIL PROTECTED] wrote:
[EMAIL PROTECTED] wrote:
I want to parse this XML file:
?xml version=1.0 ?
text
text:one
filefilename/file
contents
Hello
/contents
/text:one
text:two
filefilename2/file
contents
Hello2
/contents
Rickard Lindberg wrote:
I see two potential problems with the non regex solutions.
1) Consider a line: foo (bar). When you split it you will only get
two strings, as split by default only splits the string on white space
characters. Thus 'bar' in words will return false, even though bar is
Rickard Lindberg wrote:
I see two potential problems with the non regex solutions.
1) Consider a line: foo (bar). When you split it you will only get
two strings, as split by default only splits the string on white space
characters. Thus 'bar' in words will return false, even though bar is
Victor Polukcht wrote:
My pattern now is:
(?Pvar1[^(]+)(?Pvar2\d+)\)\s+(?Pvar3\d+)
And i expect to get:
var1 = Unassigned Number
var2 = 1
var3 = 32
I'm sure my regexp is incorrect, but can't understand where exactly.
Regex.debug shows that even the first block is incorrect.
Thanks
Hugo Ferreira wrote:
Hi!
I'm trying to do a search-replace in places where some groups are
optional... Here's an example:
re.match(rImage:([^\|]+)(?:\|(.*))?, Image:ola).groups()
('ola', None)
re.match(rImage:([^\|]+)(?:\|(.*))?, Image:ola|).groups()
('ola', '')
Hugo Ferreira wrote:
Hi!
I'm trying to do a search-replace in places where some groups are
optional... Here's an example:
re.match(rImage:([^\|]+)(?:\|(.*))?, Image:ola).groups()
('ola', None)
re.match(rImage:([^\|]+)(?:\|(.*))?, Image:ola|).groups()
('ola', '')
Matt wrote:
I am attempting to reformat a string, inserting newlines before certain
phrases. For example, in formatting SQL, I want to start a new line at
each JOIN condition. Noting that strings are immutable, I thought it
best to spllit the string at the key points, then join with '\n'.
శ్రీనివాస wrote:
Hai friends,
Can any one tell me how can i remove a character from a unocode text.
కల్హార is a Telugu word in Unicode. Here i want to
remove '' but not replace with a zero width char. And one more thing,
if any whitespaces are there before and after '' char, the text should
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