I just wrote this bit (coming from Pascal) and am wondering how seasoned Python
programmers would have done the same? Anything terribly non-python?
As always, thanks for all input.
K
Creates a PNG image from EPD file
import os, sys
from PIL import Image, ImageFont, ImageDraw
#
On Tuesday, 7 April 2015 15:43:44 UTC-7, kai.p...@gmail.com wrote:
I just wrote this bit (coming from Pascal) and am wondering how seasoned
Python programmers would have done the same? Anything terribly non-python?
As always, thanks for all input.
K
Creates a PNG image from EPD
Last week some readers have kindly supplied ideas and code for a question I had
asked around a form of image data compression required for specialized display
hardware.
I was able to solve my issues for all but one:
The black white only device (1024 (X) x 1280 (Y)) expects the compressed
On Tuesday, 24 March 2015 20:14:06 UTC-7, otaksoft...@gmail.com wrote:
I have a list containing 9600 integer elements - each integer is either 0 or
1.
Starting at the front of the list, I need to combine 8 list elements into 1
by treating them as if they were bits of one byte with 1 and 0
On Wednesday, 25 March 2015 18:10:00 UTC-7, Paul Rubin wrote:
nobody writes:
I though that the bytes type is Python 3 only? If so, I cannot use it.
In Python 2, the regular string type (str) is a byte vector, though it
is immutable. Do you send one scan line at a time to the rendering
On Tuesday, 24 March 2015 20:14:06 UTC-7, otaksoft...@gmail.com wrote:
I have a list containing 9600 integer elements - each integer is either 0 or
1.
Starting at the front of the list, I need to combine 8 list elements into 1
by treating them as if they were bits of one byte with 1 and 0
On Wednesday, 25 March 2015 20:54:21 UTC-7, kai.p...@gmail.com wrote:
I create an image as per:
img = Image.new('1', (1024, 1280), 1)
I then draw on it and do:
imagedata = list(img.getdata())
print len(imagedata)
This gives me 1228800 instead of the expected
I create an image as per:
img = Image.new('1', (1024, 1280), 1)
I then draw on it and do:
imagedata = list(img.getdata())
print len(imagedata)
This gives me 1228800 instead of the expected 1310720 (1024 * 1280)
- any ideas what I am missing?
As always, any help much
On Tuesday, 24 March 2015 21:04:37 UTC-7, Paul Rubin wrote:
nobody writes:
I have a list containing 9600 integer elements - each integer is
either 0 or 1.
Is that a homework problem? This works for me in Python 2.7 but I think
Python 3 gratuitously broke tuple unpacking so it won't work
On Tuesday, 24 March 2015 21:20:11 UTC-7, Chris Angelico wrote:
On Wed, Mar 25, 2015 at 3:04 PM, Paul Rubin nobody wrote:
This works for me in Python 2.7 but I think
Python 3 gratuitously broke tuple unpacking so it won't work there:
On Tuesday, 24 March 2015 13:15:42 UTC-7, Ian wrote:
On Tue, Mar 24, 2015 at 1:52 PM, Kai wrote:
Judging from the message archive, the image-sig list is (just about) dead?
Disclaimer: Am a newbie - so anything is possible
using 'RGB' works fine
img = Image.new('RGB',
Judging from the message archive, the image-sig list is (just about) dead?
Disclaimer: Am a newbie - so anything is possible
using 'RGB' works fine
img = Image.new('RGB', (inktile[0], inktile[1]), bgcolor)
using '1' or 'L' does not (see trace below)
img = Image.new('L',
Given
data =
'{[a=14^b=Fred^c=45.22^a=22^b=Joe^a=17^c=3.20^][a=72^b=Soup^]}'
How can I efficiently get dictionaries for each of the data blocks
framed by ?
Thanks for any help
The question here is: What _can't_ happen? For instance, what happens
if Fred's name
Given
data = '{[a=14^b=Fred^c=45.22^a=22^b=Joe^a=17^c=3.20^][a=72^b=Soup^]}'
How can I efficiently get dictionaries for each of the data blocks framed by
?
Thanks for any help
KP
--
https://mail.python.org/mailman/listinfo/python-list
Given
data =
'{[a=14^b=Fred^c=45.22^a=22^b=Joe^a=17^c=3.20^][a=72^b=Soup^]}'
How can I efficiently get dictionaries for each of the data blocks framed
by ?
Thanks for any help
The question here is: What _can't_ happen? For instance, what happens
if Fred's name contains a
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