On Dec 23, 2:04 pm, Steven D'Aprano [EMAIL PROTECTED]
cybersource.com.au wrote:
def combinations(seq, n):
if n == 0:
yield []
else:
for i in xrange(len(seq)):
for cc in combinations(seq[i+1:], n-1):
yield [seq[i]]+cc
for c in
On Mon, 24 Dec 2007 00:18:29 -0800, cf29 wrote:
On Dec 23, 2:04 pm, Steven D'Aprano [EMAIL PROTECTED]
cybersource.com.au wrote:
def combinations(seq, n):
if n == 0:
yield []
else:
for i in xrange(len(seq)):
for cc in combinations(seq[i+1:], n-1):
On Dec 23, 7:04 am, Steven D'Aprano wrote:
def combinations(seq, n):
if n == 0:
yield []
else:
for i in xrange(len(seq)):
for cc in combinations(seq[i+1:], n-1):
yield [seq[i]]+cc
for c in combinations(range(4), 3):
... print c
To make it simple and not have to deal with the 8 queens problem that
is different with the 5 queens one, I'll ask in a different way.
I am not familiar with implementing in Python such terms as standard
depth-first search of the solution space, permutation, recursion,
'canonical' form, ... I
On Sun, 23 Dec 2007 02:22:38 -0800, cf29 wrote:
How would you write a function that will populate a list with a list of
numbers with all the possibilities? For example a list of 3 numbers
taken among 4 [0,1,2,3] without duplicates. The result should be:
[0,1,2]
[0,1,3]
[0,2,3]
[1,2,3]
Greetings,
I designed in JavaScript a small program on my website called 5
queens.
(http://www.cf29.com/design/dame5_eng.php)
The goal is to control all the chess board with five queens that do
not attack each other. I found manually many solutions to this
problem (184 until now) and wanted
cf29 wrote:
Greetings,
I designed in JavaScript a small program on my website called 5
queens.
..
Has anyone tried to do a such script? If anyone is
interested to help I can show what I've done so far.
Tim Peters has a solution to 8 queens in test_generators in the standard
library
On Dec 23, 8:05 am, Dennis Lee Bieber [EMAIL PROTECTED] wrote:
On Sat, 22 Dec 2007 11:36:07 -0800 (PST), cf29 [EMAIL PROTECTED]
declaimed the following in comp.lang.python:
Greetings,
I designed in JavaScript a small program on my website called 5
queens.
Only 5? The classic
On Dec 22, 11:05 pm, Dennis Lee Bieber [EMAIL PROTECTED] wrote:
Only 5? The classic algorithm is 8-queens on a standard 8x8 board,
as I recall...
This is a different problem. You have to control all the squares with
only 5 queens.
In the 8 queens problem you have to put 8 safe queens.
I
On Dec 22, 2:36 pm, cf29 [EMAIL PROTECTED] wrote:
The goal is to control all the chess board with five queens that do
not attack each other. I found manually many solutions to this
problem (184 until now)
How did you find 184 solutions? Wolfram says there are 91 distinct
solutions for 5
Michael Spencer wrote:
Tim Peters has a solution to 8 queens in test_generators in the standard
library
test suite (see: Lib/test/test_generators.py)
and for a more straightforward and perhaps more grokkable
implementation, see Guido's original Python demo code in
Demo/scripts/queens.py
solutions? Wolfram says there are 91 distinct
solutions for 5-queens on an 8x8 board with no two queens attacking
each other.
http://mathworld.wolfram.com/QueensProblem.html
If I am not mistaken, the 92 solutions are for 8 queens on a 8x8 board
with no queen attacking each other.
On the same page
to this
problem (184 until now)
How did you find 184 solutions? Wolfram says there are 91 distinct
solutions for 5-queens on an 8x8 board with no two queens attacking
each other.
http://mathworld.wolfram.com/QueensProblem.html
If I am not mistaken, the 92 solutions are for 8 queens
On Dec 23, 1:49 am, John Machin [EMAIL PROTECTED] wrote:
How did you find 184 solutions? Wolfram says there are 91 distinct
solutions for 5-queens on an 8x8 board with no two queens attacking
each other.
It's *91* distinct solutions to what appears to be *exactly* your
problem:
k
if len(solution) nbQueens:# 5 queens
if board[i][2]==0: # free square
solution.append(i) # a queen
position
queenCtrl(board[i]) # the queen
controls
John Machin [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
| It's *91* distinct solutions to what appears to be *exactly* your
| problem:
|
|
| Dudeney (1970, pp. 95-96) also gave the following results for the
| number of distinct arrangements N_u(k,n) of k queens attacking or
|
Hi,
The problem you are trying to solve is a very famous and common
problem which can be solved by backtracking. Please try google with 8
queens problem or n queens problem.
I designed in JavaScript a small program on my website called 5
queens.
(http://www.cf29.com/design/dame5_eng.php
tried to do a such script?
ftp://ftp.visi.com/users/grante/python/queens.py
It's a pretty standard depth-first search of the solution space.
Never mind. I just realized that you said 5-queens, not
8-queens.
--
--
http://mail.python.org/mailman/listinfo/python-list
[EMAIL PROTECTED] [EMAIL PROTECTED] wrote:
Background:
The problem I'm trying to solve is.
There is a 5x5 grid.
You need to fit 5 queens on the board such that when placed there are
three spots left that are not threatened by the queen.
I know this wasn't a contest, but here's my solution
[EMAIL PROTECTED] wrote:
The problem I'm trying to solve is.
There is a 5x5 grid.
You need to fit 5 queens on the board such that when placed there are
three spots left that are not threatened by the queen.
when you're done with your homework (?), you can compare it with
Guido's solution
Fredrik Lundh wrote:
[EMAIL PROTECTED] wrote:
The problem I'm trying to solve is.
There is a 5x5 grid.
You need to fit 5 queens on the board such that when placed there are
three spots left that are not threatened by the queen.
when you're done with your homework (?), you can compare
Thank you very much guys!
Just for clarification it wasn't homework, just extra credit :)
I can't beleive I didn't realize that I didn't clear the GLOBAL
variable :D
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Em Qui, 2006-03-16 às 09:20 +0100, Fredrik Lundh escreveu:
when you're done with your homework (?), you can compare it with
Guido's solution:
http://svn.python.org/view/python/trunk/Demo/scripts/queens.py
Just a curiosity. Running the script as the site lists on my computer:
$ time
Sorry to bring this up again, but I decided to try to re-create the
program, using the 2d array.
However, I ran into a slight problem.
How will the permutation function have to be modified?
I'm having issues trying to figure out how it works, and how it would
need to be modified to use it
Fredrik Lundh [EMAIL PROTECTED] wrote:
[EMAIL PROTECTED] wrote:
The problem I'm trying to solve is.
There is a 5x5 grid.
You need to fit 5 queens on the board such that when placed there are
three spots left that are not threatened by the queen.
when you're done with your homework (?), you
Background:
The problem I'm trying to solve is.
There is a 5x5 grid.
You need to fit 5 queens on the board such that when placed there are
three spots left that are not threatened by the queen.
My thinking:
I created a list, named brd, that represents the board.
I made it such that brd[1] would
[EMAIL PROTECTED] wrote:
The first named clearbrd() which takes no variables, and will reset the
board to the 'no-queen' position.
(snip)
The Code:
#!/usr/bin/env python
brd = [9,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]
def clearbrd():
brd =
It looks like a good start! Some tips-
- Index your arrays starting from 0 instead of 1. It will make life
easier (and it's the convention in most modern languages)
- Try a two dimensional array for the board representation? A list of
lists will do:
brd = [ [0] * 5 for i in xrange(5) ]
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