[ George Sakkis ]
First of all, thanks to everyone who replied.
[ ... ]
> I don't know why you might want to distinguish between the two in
> practice (the unique object idea mentioned in other posts should
> handle most uses cases), but if you insist, here's one way to do it:
There is no act
On Feb 2, 1:30 pm, [EMAIL PROTECTED] (Igor V. Rafienko) wrote:
> Hi,
>
> I was wondering whether it was possible to find out which parameter
> value is being used: the default argument or the user-supplied one.
> That is:
>
> def foo(x, y="bar"):
> # how to figure out whether the value of y is
[EMAIL PROTECTED] (Igor V. Rafienko) writes:
> I was wondering whether it was possible to find out which parameter
> value is being used: the default argument or the user-supplied one.
> That is:
>
> def foo(x, y="bar"):
> # how to figure out whether the value of y is
> # the default argu
En Fri, 02 Feb 2007 15:30:53 -0300, Igor V. Rafienko <[EMAIL PROTECTED]>
escribió:
>> I was wondering whether it was possible to find out which parameter
> value is being used: the default argument or the user-supplied one.
> That is:
>
> def foo(x, y="bar"):
> # how to figure out whether th
Igor V. Rafienko wrote:
> I was wondering whether it was possible to find out which parameter
> value is being used: the default argument or the user-supplied one.
> That is:
>
> def foo(x, y="bar"):
> # how to figure out whether the value of y is
> # the default argument, or user-suppl
On 2007-02-02, Igor V. Rafienko <[EMAIL PROTECTED]> wrote:
> Hi,
>
> I was wondering whether it was possible to find out which
> parameter value is being used: the default argument or the
> user-supplied one. That is:
>
> def foo(x, y="bar"):
> # how to figure out whether the value of y is
>
Hi,
I was wondering whether it was possible to find out which parameter
value is being used: the default argument or the user-supplied one.
That is:
def foo(x, y="bar"):
# how to figure out whether the value of y is
# the default argument, or user-supplied?
foo(1, "bar") => user-sup
