sheffdog wrote:
> Using regular expressions, the best I can do so far is using the re.sub
> command but it still takes two lines. Can I do this in one line? Or
> should I be approaching this differently? All I want to end up with is
> the file name "ppbhat.tga".
A regular expression to do what you
Good Idea I'll try that!
Thanks for your assistance.
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"sheffdog" <[EMAIL PROTECTED]> wrote:
> Using basename works, but leaves the extra stuff at the end.
> Which would have to be removed with another line of code
>
> I get this--> ppbhat.tga";
if you're trying to parse Maya files, maybe you should start
by writing a simple Maya parser, and use
Using basename works, but leaves the extra stuff at the end.
Which would have to be removed with another line of code
I get this--> ppbhat.tga";
Thanks, for the idea though.
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May not be what you are looking for, but this works:
import os
s='setAttr ".ftn" -type "string" ' \
'/assets/chars/boya/geo/textures/lod1/ppbhat.tga";'
fname=os.path.basename(s.split()[-1])
BTW-It does depend on the file/path being the last item
on the line.
Larry Bates
sheffdog wrote:
> He
"sheffdog" <[EMAIL PROTECTED]> wrote:
> setAttr ".ftn" -type "string" /assets/chars/
>/boya/geo/textures/lod1/ppbhat.tga";
> Can I do this in one line?
>>> os.path.basename("/assets/chars/.../lod1/ppbhat.tga")
'ppbhat.tga'
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Hello,
I often find myself cleaning up strings like the following:
setAttr ".ftn" -type "string" /assets/chars/
/boya/geo/textures/lod1/ppbhat.tga";
Using regular expressions, the best I can do so far is using the re.sub
command but it still takes two lines. Can I do this in one line? O
