> How can I convert a string "0x62" to int/hex without this problem?
The call to int() takes an optional parameter for the base:
>>> print int.__doc__
int(x[, base]) -> integer
Convert a string or number to an integer, if possible. A
floating point argument will be truncated towards zero (thi
Ognjen Bezanov enlightened us with:
> Hi all, I am trying to convert a hexdecimal value to a char using this code:
>
> print ' %c ' % int(0x62)
This is an integer
> this works fine, but if I want to do this:
>
> number = "62"
> print ' %c ' % int("0x" + number)
This is a string ^^^
Hi all, I am trying to convert a hexdecimal value to a char using this code:
print ' %c ' % int(0x62)
this works fine, but if I want to do this:
number = "62"
print ' %c ' % int("0x" + number)
I get an error:
Traceback (most recent call last):
File "",line 1, in ?
ValueError: invalid literal
