On Dec 4, 2007 10:40 AM, Nick [EMAIL PROTECTED] wrote:
Is this expected behavior?
s = '123;abc'
s.replace(';', '\;')
'123\\;abc'
Everything is Ok. It's still a single backslash. Try:
print s.replace(';', '\;')
Or
x = s.replace(';', '\;')
print x
Best,
Sergio
--
Nick a écrit :
Hi all,
Is this expected behavior?
s = '123;abc'
s.replace(';', '\;')
'123\\;abc'
print s.replace(';', '\;')
123\;abc
I just wanted a single backslash.
You got it - even if it's not obvious !-)
I can see why this probably happens
but i wondered if it is definitely
Nick wrote:
Hi all,
Is this expected behavior?
s = '123;abc'
s.replace(';', '\;')
'123\\;abc'
I just wanted a single backslash. I can see why this probably happens
but i wondered if it is definitely intentional.
There is only a single backslash. But the interactive prompt will use
Hi all,
Is this expected behavior?
s = '123;abc'
s.replace(';', '\;')
'123\\;abc'
I just wanted a single backslash. I can see why this probably happens
but i wondered if it is definitely intentional.
Thanks
Nick
--
http://mail.python.org/mailman/listinfo/python-list
Is this expected behavior?
s = '123;abc'
s.replace(';', '\;')
'123\\;abc'
You're asking the interpreter to print a representation of your
string, so it does so. Representations wrap the results in
quotes and escape characters within that need escaping.
s.replace(';', '\;')
'123\\;abc'
Nick wrote:
Is this expected behavior?
s = '123;abc'
s.replace(';', '\;')
'123\\;abc'
I just wanted a single backslash. I can see why this probably happens
but i wondered if it is definitely intentional.
What you're seeing on the screen is a literalization of the string
value for the
Thanks guys, you answered that interactive prompt question really
clearly however, whats going on here. This works now -
working_string = '123;abc'
search_string = ';'
print working_string.replace(search_string, '\\' + search_string)
123\;abc
But this doesn't -
---
import sys
import string
On Dec 4, 2007 11:33 AM, Nick [EMAIL PROTECTED] wrote:
Try 123 *?/ abc d;o /$' as the argument... and you get -
123 \*\?\/ abc d\\;o \/\$
That's because of the order you're doing the replacement. Put a print
statement inside your for loop and you'll see something like this:
input starts as
If you move '\\' to the front of your list of replacement characters,
things will probably work as you expect.
--
Jerry
I knew it would be something like that! Thanks for your help.
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