Steve,
the os commands don't run through zope, it denies access to them to be
run at all through the webserver. So in turn, I had to use a work
around to fix the IE problem. Also qwwee's suggestion to use:
filepath.split('\\')[-1]
works well too. Zope is very finicky about running specific
mjakowlew wrote:
Steve,
the os commands don't run through zope, it denies access to them to be
run at all through the webserver. So in turn, I had to use a work
around to fix the IE problem. Also qwwee's suggestion to use:
filepath.split('\\')[-1]
works well too. Zope is very finicky
I just assumed he had heard of me and knew better than to take my
advice. :-)
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Thanks guys. The os.path method works, but this is for a script for a
website upload program on a zope webserver. For some reason even admin
access won't let me run the script through the server.
The main issue with my script is that Firefox has no problem with the
program the way it is, but IE
Hi mjakowlew,
to get file basename in Linux I use simply:
filepath.split('/')[-1]
But in Windows, being the dir separator '\',
you get into trouble if the dir or file name begins
with one of the escape sequences:
\a ASCII Bell(BEL) \x07
\b ASCII Backspace (BS) \x08
\f
I got the IE Fix working, here's the code:
path = r'c:\here\there\files\file.ext'
i=len(path)
j=0
size=len(path)
while i:
i=i-1
if path[i]== '\\':
j=i+1
break
filename = path[j:size]
print FILENAME: %s %(filename)
___
Most
mjakowlew wrote:
I got the IE Fix working, here's the code:
path = r'c:\here\there\files\file.ext'
i=len(path)
j=0
size=len(path)
while i:
i=i-1
if path[i]== '\\':
j=i+1
break
filename = path[j:size]
print FILENAME: %s %(filename)
Hi,
I'm trying to use some string manipulation from a file's path.
filepath='c:\documents\web\zope\file.ext'
I need to extract everthing after the last '\' and save it.
I've looked around and have tried the sub, search, match commands, but
I'm guessing '\' is set aside for switches. I need to
import os
print os.path.basename(filepath)
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mjakowlewwrote:
filepath='c:\documents\web\zope\file.ext'
I need to extract everthing after the last '\' and save it.
that string doesn't contain what you think it does:
filepath='c:\documents\web\zope\file.ext'
filepath
'c:\\documents\\web\\zope\x0cile.ext'
print filepath
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