James Stroud wrote:
def stream_factory:
class Line(object):
__source = source
__join = join
# etc.
return Line
of course I meant def stream_factory(lines, source, join=''.join):
James
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andrew cooke wrote:
On Aug 12, 7:49 am, andrew cooke and...@acooke.org wrote:
On Aug 12, 1:51 am, James Stroud nospamjstroudmap...@mbi.ucla.edu
wrote:
andrew cooke wrote:
Is there a way to make this work (currently scope and join are
undefined at runtime when the inner class
On Wed, 12 Aug 2009 04:49:06 -0700, andrew cooke wrote:
It would be helpful if you were to describe the type of behavior you
expect.
Sorry, I didn't make myself clear. When run the code gives
NameError: name 'source' is not defined
because the class namespace blocks the function
andrew cooke wrote:
Is there a way to make this work (currently scope and join are
undefined at runtime when the inner class attributes are defined):
class _StreamFactory(object):
@staticmethod
def __call__(lines, source, join=''.join):
class Line(object):
On Aug 12, 8:52 am, Dave Angel da...@ieee.org wrote:
Supply us with just enough source code to actually try it, give the full
error message including traceback, and tell us what you expected to
see. Also tell us Python version (sys.version)
So far you've done none of these. When I try the
Is there a way to make this work (currently scope and join are
undefined at runtime when the inner class attributes are defined):
class _StreamFactory(object):
@staticmethod
def __call__(lines, source, join=''.join):
class Line(object):
__source = source
correction: source and join are undefined. Sorry, Andrew
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andrew cooke wrote:
Is there a way to make this work (currently scope and join are
undefined at runtime when the inner class attributes are defined):
class _StreamFactory(object):
@staticmethod
def __call__(lines, source, join=''.join):
class Line(object):
