[EMAIL PROTECTED] writes:
> When I try your idea, I have this error
>
> x, y, width, height = re.findall(pattern, str)[0]
> IndexError: list index out of range
>
> How can I use findall to handle error case? i.e. what if there is no
> match? how can I handle it gracefully?
This is explained i
When I try your idea, I have this error
x, y, width, height = re.findall(pattern, str)[0]
IndexError: list index out of range
How can I use findall to handle error case? i.e. what if there is no
match? how can I handle it gracefully?
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Are you sure node.data contains newlines?
You could try just:
print node.data
print node.data.split('\n')
This should give you an idea. From the interpreter:
>>> s = """
... abc
... def
... xyz"""
>>> s.split('\n')
['', 'abc', 'def', 'xyz']
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okay, but I have a simpler question, how can I split using only "\n"?
I try this:
strings = node.data.split("\n");
print node.data
for str in strings:
print str
where node.data has multiple lines, but in the for loop, I don't see
str gets pr
You don't really need regexes for this.
Assuming there is no whitespace in any of your values, it should be
really easy to parse the string.
s = 'x:11 y:0 w:760 h:19 area:14440 areaPerCent:0
totalAreaPerCent:-3.08011e+16 type:3 path:///-/1/1'
s.split() # break the string on whitespace
> ['x:11',
Thanks. But i don't understand why I need to do this:
x. . area = map (lambda x: int(x), re.findall (pattern, line)[0]
if i have the value already by doing this:
x, y, width, height, area = re.findall(pattern, line)[0]
print "rect x=\"%(x)s\" y=\"%(y)s\" width=\"%(width)s\"
height=\"%(height)s\"
[EMAIL PROTECTED] writes:
> Hi,
> I am new to python. I would like to know how to use python regular
> expression to substitute string value?
> I have an input string like this:
> x:11 y:0 w:760 h:19 area:14440 areaPerCent:0
> totalAreaPerCent:-3.08011e+16 type:3 path:///-/1
Hi,
I am new to python. I would like to know how to use python regular
expression to substitute string value?
I have an input string like this:
x:11 y:0 w:760 h:19 area:14440 areaPerCent:0
totalAreaPerCent:-3.08011e+16 type:3 path:///-/1/1
and I would like to convert it to:
rect x="11&
