On Sunday, July 6, 2014 3:26:44 PM UTC-4, Ian wrote:
On Sun, Jul 6, 2014 at 12:57 PM, rxjw...@gmail.com wrote:
I write the following code:
...
import re
line = abcdb
matchObj = re.match( 'a[bcd]*b', line)
if matchObj:
print matchObj.group() : ,
rxjw...@gmail.com writes:
Because I am new to Python, I may not describe the question clearly. Could you
read the original problem on web:
https://docs.python.org/2/howto/regex.html
It says that it gets 'abcb'. Could you explain it to me? Thanks again
Actually, it tries to explain how *
On Mon, Jul 7, 2014 at 7:30 AM, rxjw...@gmail.com wrote:
Because I am new to Python, I may not describe the question clearly. Could you
read the original problem on web:
https://docs.python.org/2/howto/regex.html
It says that it gets 'abcb'. Could you explain it to me? Thanks again
The
Hi,
On Python website, it says that the following match can reach 'abcb' in 6 steps:
.
A step-by-step example will make this more obvious. Let's consider the
expression
a[bcd]*b. This matches the letter 'a', zero or more letters from the class
[bcd],
and finally ends with a 'b'.
On 2014-07-06 19:57, rxjw...@gmail.com wrote:
Hi,
On Python website, it says that the following match can reach 'abcb' in 6 steps:
.
A step-by-step example will make this more obvious. Let's consider the
expression
a[bcd]*b. This matches the letter 'a', zero or more letters from
On Sun, Jul 6, 2014 at 12:57 PM, rxjw...@gmail.com wrote:
I write the following code:
...
import re
line = abcdb
matchObj = re.match( 'a[bcd]*b', line)
if matchObj:
print matchObj.group() : , matchObj.group()
print matchObj.group(0) : , matchObj.group()
print
