cypher543 wrote:
> That was a very good answer, and it sure sounds like it would work.
> However, I failed at implementing it. :( My updated runQueue() function
> is:
>
> def runQueue(self):
> self.buildProcess = None
> count = 1 # current position in the queue
> while True:
>
That was a very good answer, and it sure sounds like it would work.
However, I failed at implementing it. :( My updated runQueue() function
is:
def runQueue(self):
self.buildProcess = None
count = 1 # current position in the queue
while True:
if self.buildPr
cypher543 wrote:
> self.buildPID = subprocess.Popen(buildCmd, stdout = subprocess.PIPE, stderr =
> subprocess.STDOUT)
Instead of calling it self.buildPID, you might just call it
self.buildProcess or something. It's actually a Popen object that gets
returned.
So yes you can do what you want:
_
My app uses a "queue" of commands which are run one at a time. I am
using the subprocess module to execute the commands in the queue.
However, processes always run at the same time. How can I make one
process run at a time, and then execute the next process when the first
has terminated? My code is
