Tim Chase wrote:
success = None
for i in range(5):
#Try to fetch public IP
success = CheckIP()
if success:
break
if not success:
print Exiting.
sys.exit()
Though a bit of an abuse, you can use
if not any(CheckIP() for _ in range(5)):
print Exiting
success = None
for i in range(5):
#Try to fetch public IP
success = CheckIP()
if success:
break
if not success:
print Exiting.
sys.exit()
Though a bit of an abuse, you can use
if not any(CheckIP() for _ in range(5)):
print Exiting
sys.exit()
I don't see
Gilles Ganault wrote:
Hello
As a newbie, it's pretty likely that there's a smarter way to do this,
so I'd like to check with the experts:
I need to try calling a function 5 times. If successful, move on; If
not, print an error message, and exit the program:
=
success = None
for
On Thu, Nov 20, 2008 at 11:58 PM, Steve Holden [EMAIL PROTECTED] wrote:
Gilles Ganault wrote:
Hello
As a newbie, it's pretty likely that there's a smarter way to do this,
so I'd like to check with the experts:
I need to try calling a function 5 times. If successful, move on; If
Tim Chase wrote:
success = None
for i in range(5):
#Try to fetch public IP
success = CheckIP()
if success:
break
if not success:
print Exiting.
sys.exit()
Though a bit of an abuse, you can use
if not any(CheckIP() for _ in range(5)):
print Exiting
Hello
As a newbie, it's pretty likely that there's a smarter way to do this,
so I'd like to check with the experts:
I need to try calling a function 5 times. If successful, move on; If
not, print an error message, and exit the program:
=
success = None
for i in range(5):
#Try to
I need to try calling a function 5 times. If successful, move on; If
not, print an error message, and exit the program:
success = None
for i in range(5):
#Try to fetch public IP
success = CheckIP()
if success:
break
if not success:
print Exiting.
Gilles Ganault [EMAIL PROTECTED] wrote:
As a newbie, it's pretty likely that there's a smarter way to do this,
so I'd like to check with the experts:
I need to try calling a function 5 times. If successful, move on; If
not, print an error message, and exit the program:
=
success = None
for
On Nov 19, 2008, at 09:09, Gilles Ganault wrote:
Hello
As a newbie, it's pretty likely that there's a smarter way to do this,
so I'd like to check with the experts:
I need to try calling a function 5 times. If successful, move on; If
not, print an error message, and exit the program:
=
On 19 Nov 2008 14:37:06 + (GMT), Sion Arrowsmith
[EMAIL PROTECTED] wrote:
Note very carefully that the else goes with the for and not the if.
Thanks guys.
--
http://mail.python.org/mailman/listinfo/python-list
On Nov 19, 10:21 am, Gilles Ganault [EMAIL PROTECTED] wrote:
On 19 Nov 2008 14:37:06 + (GMT), Sion Arrowsmith
[EMAIL PROTECTED] wrote:
Note very carefully that the else goes with the for and not the if.
Thanks guys.
And if you end up doing this for several different functions, you can
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