On 4/10/2023 9:59 AM, Jack Gilbert wrote:
I D/L 3.11.3, I can see it in CMD
running W10 64bit
I have IDL on my desktop,
HOW do I get 3.11.3 on my desktop?
If you mean "How can I create a shortcut to Python 3.11.3 on my desktop
that opens an interactive Python session", here is one way:
1.
use where cmd to find out the path of the binary and create a shortcut to
that file on desktop
Regards,
*Sravan Chitikesi*
AWS Solutions Architect - Associate
On Mon, Apr 10, 2023 at 10:03 AM Jack Gilbert <00jhen...@gmail.com> wrote:
> I D/L 3.11.3, I can see it in CMD
>
> running W10 64bit
>
>
I D/L 3.11.3, I can see it in CMD
running W10 64bit
I have IDL on my desktop,
HOW do I get 3.11.3 on my desktop?
Thanks
Jack g
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On 23/11/2013 22:29, Bhanu Karthik wrote:> On Saturday, 23 November 2013
14:23:08 UTC-8, Chris Angelico wrote:
>> On Sun, Nov 24, 2013 at 9:15 AM, Bhanu Karthik
>> wrote:
>> > data = sock.recv(RECV_BUFFER)
>> > username = str(sock.getpeername())
>> >
On Sun, Nov 24, 2013 at 9:39 AM, Bhanu Karthik
wrote:
> indentation is correct when I trying to paste it here,it is showing like it
> is unindented.
That's because Google Groups mucks things up. Get a better client.
ChrisA
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On Saturday, 23 November 2013 14:37:09 UTC-8, Roy Smith wrote:
> In article <8445e47e-7efe-4f37-9b40-db2896d58...@googlegroups.com>,
>
> Bhanu Karthik wrote:
>
>
>
> > data = sock.recv(RECV_BUFFER)
>
> > username = str(sock.getpeername())
>
> >
On Sun, Nov 24, 2013 at 9:33 AM, Bhanu Karthik
wrote:
> this is exact code..
> it is not even entering the if ...
> I tried ( c= (data is '/quit')if c)
>
> when i print c ,its printing falseI dont understand what is
> happening...please help..
Again, please get off Google Groups. Have a look
In article <8445e47e-7efe-4f37-9b40-db2896d58...@googlegroups.com>,
Bhanu Karthik wrote:
> data = sock.recv(RECV_BUFFER)
> username = str(sock.getpeername())
> username = usernames[username]
> if data == "/quit"
On Saturday, 23 November 2013 14:23:08 UTC-8, Chris Angelico wrote:
> On Sun, Nov 24, 2013 at 9:15 AM, Bhanu Karthik
>
> wrote:
>
> > data = sock.recv(RECV_BUFFER)
>
> > username = str(sock.getpeername())
>
> > username = usernames[usern
On Sun, Nov 24, 2013 at 9:29 AM, Bhanu Karthik
wrote:
> sorry its not command its data
>
> I miss wrote it here...
Okay. Start by copying and pasting your actual code, and saying what
you're doing to trigger it. If this is a stream socket (eg TCP), you
have no way of knowing where one read wi
On Saturday, 23 November 2013 14:23:08 UTC-8, Chris Angelico wrote:
> On Sun, Nov 24, 2013 at 9:15 AM, Bhanu Karthik
>
> wrote:
>
> > data = sock.recv(RECV_BUFFER)
>
> > username = str(sock.getpeername())
>
> > username = usernames[usern
On Sun, Nov 24, 2013 at 9:15 AM, Bhanu Karthik
wrote:
> data = sock.recv(RECV_BUFFER)
> username = str(sock.getpeername())
> username = usernames[username]
> if command == "/quit":
>
data = sock.recv(RECV_BUFFER)
username = str(sock.getpeername())
username = usernames[username]
if command == "/quit":
print data
sock.send("bye"
On 06/08/2011 11:59 PM, Larry Hudson wrote:
On 06/08/2011 01:09 PM, Cathy James wrote:
I am almost there, but I need a little help:
I would like to
...
Here's one possible replacement. There are many other approaches as well.
(This leaves the individual dogs as a (name, breed) tuple. It co
Ethan Furman wrote:
Larry Hudson wrote:
On 06/08/2011 01:09 PM, Cathy James wrote:
Dog Breed: "))
while not dogs:
print("Goodbye!!")
sys.exit()
else:
else does not belong with while.
else works just fine with while; it is the path taken when the while is
exhaust
Larry Hudson wrote:
On 06/08/2011 01:09 PM, Cathy James wrote:
Dog Breed: "))
while not dogs:
print("Goodbye!!")
sys.exit()
else:
else does not belong with while.
else works just fine with while; it is the path taken when the while is
exhausted, but not broken ou
On 06/08/2011 01:09 PM, Cathy James wrote:
I am almost there, but I need a little help:
I would like to
a) print my dogs in the format index. name: breed as follows:
0. Mimi:Poodle
1.Sunny: Beagle
2. Bunny: German Shepard
I am getting
(0, ('Mimi', 'Poodle')) . Mimi : Poodle instead-what have
In Cathy James
writes:
> b) I would like to append to my list, but my line dogs.dogAppend() is
> giving a TypeError:
> for i in enumerate (self.dogAppend()):
> TypeError: 'list' object is not callable
> def dogAppend(self):
> self.dogAppend = []
You have a method and a list that
On Wed, Jun 8, 2011 at 1:09 PM, Cathy James wrote:
> I am almost there, but I need a little help:
>
> I would like to
>
> a) print my dogs in the format index. name: breed as follows:
>
> 0. Mimi:Poodle
> 1.Sunny: Beagle
> 2. Bunny: German Shepard
> I am getting
>
> (0, ('Mimi', 'Poodle')) . Mimi
Cathy James wrote:
I am almost there, but I need a little help:
I would like to
a) print my dogs in the format index. name: breed as follows:
0. Mimi:Poodle
1.Sunny: Beagle
2. Bunny: German Shepard
I am getting
(0, ('Mimi', 'Poodle')) . Mimi : Poodle instead-what have I done wrong?
b) I wou
I am almost there, but I need a little help:
I would like to
a) print my dogs in the format index. name: breed as follows:
0. Mimi:Poodle
1.Sunny: Beagle
2. Bunny: German Shepard
I am getting
(0, ('Mimi', 'Poodle')) . Mimi : Poodle instead-what have I done wrong?
b) I would like to append to
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